A. T. S.A =2* AREA OF TRIANGLE +PREIMETER*5.56
VOLUME=AREA OF *LENGTH[ 5.56]
B. T. S. A=πR{R + SLANT HIGHT }
VOLUME=1/3*π*R*HIGHT{ 7 }
volume of a sphere is 3 by 4 by R cube and surface area of a sphere is 4 Pi R Square
0.4 is four tenths. 0.4 = 4/10=2/5
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
the croccect amswer is A
Step-by-step explanation:
