PLEASE ANSWER NOW FOR A TEST

According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a

Likurg_2 [28]

Answer:

1) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) $0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

$X = 157$ represent the women who worked at home who were college graduates

$n = 480$ the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

$\hat p=\frac{X}{n} = \frac{157}{480}= 0.327$

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 80% confidence interval the value for the significance is $\alpha=1-0.8=0.2$ and $\alpha/2=0.1$ , the critical value would be given by:

$z_{\alpha/2}=0.539$

And replacing we goot:

$0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315$

$0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339$

The 80% confidence interval is given by (0.315; 0.339)

6 0

3 years ago

Suppose that f (x) = 1.5x2 for -1 < x < 1 and f (x) = 0 otherwise. Determine the following probabilities.

BabaBlast [244]

Answer:

a) P(0 < X) = 0.5

b) P(0.5 < X) = 0.4375

c) P(-0.5 = X = 0.5) = 0.125

d) P(X< -2) = 0

e) P(X < 0 or X>-0.5) = 1

f) value of x is -0.9654

Step-by-step explanation:

Given that;

f(x) = 1.5x²

Now. the probabilities would be the integral of the given function from (-1 to 1)

a) P(0 < X)

P(X > 0)

⇒ Integral from 0 to 1 of f(x)

= (1/2)x³

= 1/2 - 0

= 0.5

Therefore; P(0 < X) = 0.5

b) P(0.5 < X)

P(X > 0.5)

this will also be done in the same way except that, the limits changes to { 0.5 to 1]

= (1)³/2 - (0.5)³ /2

= 0.4375

Therefore; P(0.5 < X) = 0.4375

c) P(-0.5 = X = 0.5)

The limits become [-0.5 , 0.5]

= (0.5)³/2 - (-0.5)³/2

= 0.125

Therefore; P(-0.5 = X = 0.5) = 0.125

d) P(X<-2)

since value of f(x) = 0 in that region

Therefore P(X< -2) = 0

e) P(X < 0 or X>-0.5)

= P(X < 0) + P(X > -0.5) - P( -0.5 < X < 0 )

= 0.5 + 0.5625 - 0.0625

= 1

Therefore; P(X < 0 or X>-0.5) = 1

f) Determine x such that P(x < X) = 0.05.

Let the value be 'a'

Then, integral from -1 to a will = 0.05

a³ - (-1)³ = 0.05 × 2

a³ + 1 = 0.10

a³ = 0.10 - 1

a³ = -0.9

a = ∛-0.9

a = -0.9654

Therefore, value of x is -0.9654

8 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

nignag [31]

Answer:

log 5 + log 2 = 1

8 0

3 years ago

First right answer gets brainlist

SVETLANKA909090 [29]

1 2/3 divided by .8 is 2 and 1/12 so the answer is C

7 0

4 years ago

-

Lelechka [254]

B is the correct answer. 3(x+1)=24

6 0

3 years ago