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Alla [95]
3 years ago
13

PLEASE ANSWER NOW FOR A TEST

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0
I think it might be b
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Which would be appropriate compatible numbers to use to estimate (19 4/5) (4/6) A. 16(1/3) B. 19(2/3) C. 20(1/2) D. 20(1)
podryga [215]

Answer:

C. 20(1/2)

Step-by-step explanation:

Let's find the value of the expression before looking for the nearest estimate

(19 4/5) (4/6) = 19 *(4/5)(4/6)

(19 4/5) (4/6) = 19(16/30)

(19 4/5) (4/6) = 19(8/15)

(19 4/5) (4/6) = (19*8)/15

(19 4/5) (4/6) = 152/15

(19 4/5) (4/6) = 10(2/15)

A. 16(1/3) =5.33

B. 19(2/3) = 12.667

C. 20(1/2) = 10

D. 20(1)= 20

The nearest to the expression is C. 20(1/2)

6 0
3 years ago
11. Square ABCD shown has sides of length 10 centimeters. The unshaded
enyata [817]

Answer:

21cm^2

Step-by-step explanation:

Area of Square-Area of semi circles (makes one full circle)

Squares Area = 100

LxW or (10x10)=100

Circle Area = 25/pi

/pi (radius)^2 or /pi(5)^2 = 25/pi

100cm^2-25cm^2 = 21.4601…cm^2 rounded to 21.5 cm^2

6 0
3 years ago
Weekly demand for a particular item averages 30 units, with a standard deviation of 4. This item is managed with a fixed-order-i
aivan3 [116]

Answer:

(B)93

Explanation:

Since we are using a fixed-order-interval model,

The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand

=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A

Where:  

d=weekly demand

OI=Order Interval

LT=Lead Time

z=Standard Deviation of Desired Service Level

\sigma_{d}=Standard Deviation of weekly Demand

A= Amount at Hand

=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A

[30(3 + 1)] + [1.964*4*\sqrt{3 + 1} - 43

= 120 + 15.712 - 43 = 92.7

4 0
3 years ago
A constant of proportionality can also be considered a(n) unit rate. y-value. x-value. ratio.
lilavasa [31]

Answer:

A. Unit rate.

Step-by-step explanation:

We have been given a statement and we are supposed to choose the correct option for our given statement.

Statement:

A constant of proportionality can also be considered a(n) <u>          </u> .

Since we know that constant of proportionality represents the amount by which two proportional quantities vary.

Two quantities are directly proportional, when they are in form y=kx, where k represents the constant of proportionality.

We can represent this proportion also as: k=\frac{y}{x}

Since k represents the quotient of y and x, so the value of k represents the unit rate for two quantities y and x, therefore, a constant of proportionality can also be considered an unit rate.

7 0
4 years ago
Read 2 more answers
I’m so confused on how to find the answer to this
nalin [4]

Step-by-step explanation:

download an app called algebrator its way easier than asking brainly

4 0
3 years ago
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