Answer:
Sedan: 4 passengers
Minivan: 6 passengers
Step-by-step explanation:
We can write the following system of equations:
, where
represents the number of people a sedan can seat and
represents the number of people a minivan can seat.
Subtracting the first equation from the second, we have:
![2s+2m-(2s+1m)=20-14,\\\\m=6](https://tex.z-dn.net/?f=2s%2B2m-%282s%2B1m%29%3D20-14%2C%5C%5C%5C%5Cm%3D6)
Now plug in
in any of the equations to solve for
:
![2s+1(6)=14, \\2s=8, \\s=4](https://tex.z-dn.net/?f=2s%2B1%286%29%3D14%2C%20%5C%5C2s%3D8%2C%20%5C%5Cs%3D4)
Verify that the solution pair
works:
![2(4)+1(6)=14\: \checkmark \\2(4)+2(6)=20 \: \checkmark](https://tex.z-dn.net/?f=2%284%29%2B1%286%29%3D14%5C%3A%20%5Ccheckmark%20%5C%5C2%284%29%2B2%286%29%3D20%20%5C%3A%20%5Ccheckmark)
Therefore, a sedan can hold 4 passengers and a minivan can hold 6 passengers.
The answer is: 45 * 10 ⁻¹¹ .
___________________________________________
Explanation:
____________________________________________
Given: (9 * 10⁻⁵) * (5 *10 ⁻⁶) ; Simplify.
____________________________________________
(9 * 10⁻⁵) * (5 *10⁻⁶) =
9 * 5 * 10⁻⁵ * 10⁻⁶ =
(9 * 5) * 10⁻⁵ * 10⁻⁶
45 * 10⁻⁵ * 10⁻⁶ ;
______________________________________
Note the following property of exponents:
xᵃ * xᵇ = x⁽ᵃ⁺ᵇ⁾ ;
As such, 10⁻⁵ * 10⁻⁶ = 10⁽⁻⁵ ⁺ ⁻⁶) = 10 ⁻¹¹ ;
______________________________________
So; 45 * 10⁻⁵ * 10⁻⁶
= 45 * 10⁻¹¹ .
______________________________________
Answer:
1/7
Step-by-step explanation:
There are seven people in all on person will arrive at a different time than others. Every single one of them arrives at different times so it's 1/7
Answer:
christopher columbus
Step-by-step explanation:
First subtract 325-7= 318 Then you divide 318/6=53
So each bus holds 53 people