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Ahat [919]
3 years ago
6

Which of the equations below could be the equation of this parabola? A y = 1/6x2 B. x = -1/6y2 C. x = 1/6y2 D. y = -1/6x2

Mathematics
1 answer:
Schach [20]3 years ago
7 0

Answer:

C

Step-by-step explanation:

assuming the 2s are all squares

just plot a point and it's negative

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If (2x,3y) =(8, 9),find x and y​
solong [7]

Answer:

x = 4, y = 3

Step-by-step explanation:

Equating corresponding coordinates , gives

2x = 8 ( divide both sides by 2 )

x = 4

and

3y = 9 ( divide both sides by 3 )

y = 3

5 0
2 years ago
I WILL GIVE YOU BRAINLIEST PLEASE HELPPPPP
Vanyuwa [196]

Answer: 3/2

Step-by-step explanation:

Let's consider the points (6,9) and (4,6).

The difference in the y coordinates is 3, and the diffeence in the x coordinates is 2.

So, the slope is 3/2.

3 0
2 years ago
What number can you put in the missing spot of the domain to keep the table a function? Select all that apply.​
Bingel [31]

Answer:

1,8 and 5,10

Step-by-step explanation:

5 0
3 years ago
Quadrilateral ABCD has diagonals that are congruent and perpendicular to each other. What classification can be given to ABCD? (
Anuta_ua [19.1K]
The answer to ur question will be a square since all diagonals are congruent and bisect each other at right angles
Note:'this is not applicable for the other quadrilaterals from the given options'
Hope this helps u..!!!
Good luck!
8 0
3 years ago
What is the midpoint of AB please help
storchak [24]

Answer:

Hint: 0 is x1, -2 is y1, 10 is x2, and -6 is y2.

Step-by-step explanation:

I'm not sure how to explain it, but that's how you can label your coordinates to  make it easier to substitute it into the formula. The first number at the beginning of the coordinate is x and the other is y. For example, (3, 7). The three is x and the seven y. If you have two coordinates, then one group has a 1 underneath it while the other has a 2. Simply put, (x1, y1) and (x2, y2). The only thing left is to find the midpoint of segment AB (or line, not sure) by using the midpoint formula.

(If you still need help, you can always reply back)

3 0
2 years ago
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