Answer:2
Step-by-step explanation: 5 - 3 = 2
Answer:
The answer is 8.30
Step-by-step explanation:
Using cos 41 = x/11
x = cos 41 × 11
x = 8.30
26 would be the correct answer because 2/3 X 40 = 26.667 but you cant serve a little bit of soup so the total would be 26 Hoped this helped
Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that
Standard deviation,
ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.
![P(x\geq 10)=0.99](https://tex.z-dn.net/?f=P%28x%5Cgeq%2010%29%3D0.99)
Assume the bag weight distribution is bell-shaped
Therefore,
![P(\frac{x-\mu}{\sigma}\geq 10)=0.99](https://tex.z-dn.net/?f=P%28%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cgeq%2010%29%3D0.99)
We know that
![z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Using the value of z
Now,
![\frac{10-\mu}{0.2}=0.99](https://tex.z-dn.net/?f=%5Cfrac%7B10-%5Cmu%7D%7B0.2%7D%3D0.99)
![10-\mu=0.99\times 0.2](https://tex.z-dn.net/?f=10-%5Cmu%3D0.99%5Ctimes%200.2)
![\mu=10-0.99\times 0.2](https://tex.z-dn.net/?f=%5Cmu%3D10-0.99%5Ctimes%200.2)
![\mu=9.802](https://tex.z-dn.net/?f=%5Cmu%3D9.802)
Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Answer:
A) x-8
Step-by-step explanation:
![\mathsf{5x^2-40x=5x(x-8)}](https://tex.z-dn.net/?f=%5Cmathsf%7B5x%5E2-40x%3D5x%28x-8%29%7D)
because
![\mathsf{5x(x-8)=5x\cdot x-5x\cdot8=5x^2-40x}](https://tex.z-dn.net/?f=%5Cmathsf%7B5x%28x-8%29%3D5x%5Ccdot%20x-5x%5Ccdot8%3D5x%5E2-40x%7D)