Answer:
a) 
b) 
And replacing we got:
![P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.2%2B0.3%2B0.1%5D%3D%200.4)
c) 
d) 
e) 
f) 
And replacing we got:
And the variance would be:
![Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4](https://tex.z-dn.net/?f=%20Var%28X0%20%3DE%28X%5E2%29-%20%5BE%28X%29%5D%5E2%20%3D%206.4%20-%282%5E2%29%3D%202.4)
And the deviation:
Step-by-step explanation:
We have the following distribution
x 0 1 2 3 4
P(x) 0.2 0.3 0.1 0.1 0.3
Part a
For this case:
Part b
We want this probability:
And replacing we got:
Part c
For this case we want this probability:
Part d
Part e
We can find the mean with this formula:
And replacing we got:
Part f
We can find the second moment with this formula
And replacing we got:
And the variance would be:
And the deviation:
This question is incomplete
Complete Question
Leah is creating satin bows for a wedding. From a 15-meter-long ribbon, she first cuts a piece 3 4/9 meters long. Then she cuts a piece 6 5/9 meters long from the remaining ribbon. How much ribbon does Leah have left?
A.) -12 meters
B.) -5 meters
C.) 5 meters
D.) 12 meters
Answer:
C.) 5 meters
Step-by-step explanation:
From a 15-meter-long ribbon, she first cuts a piece 3 4/9 meters long. Then she cuts a piece 6 5/9 meters long from the remaining ribbon.
Step 1
3 4/9 meters + 6 5/9 meters
Least Common Denominator = 9
(3+ 6) + [ 4/9 + 5/9)
9 + [4 + 5/9]
9 + [9/9]
9 + 1
= 10 meters
This means, the total number of ribbons cut is 10 meters
The amount of ribbon Leah has left =
Initial length of ribbon - Amount of ribbon cut
= 15 meters - 10 meters
= 5 meters
Hence, Leah has 5 meters long of ribbon left
Answer:
the answer is 4/8 and pls make me a brainiest and follow me
That depends on your definition of "whole numbers." In the positive integers, there are twenty pairs: (1, 39), (2, 38), ... (20, 20).
Rigid Motion
Step-by-step explanation:
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