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3 years ago

24. What term describes a transformation that does

Mathematics

2 answers:

goldenfox [79]3 years ago

5 0

Rigid Motion

Step-by-step explanation:

...........

Makovka662 [10]3 years ago

5 0

Answer:

letter c.collinearity po sagot diyan

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Help look at picture ;-;

GaryK [48]

Answer:

Step-by-step explanation:

turn the 4/3 into a decimal.=1.33

multiply 1.33*3.14=4.1762

i cant see the rest is it r³?

4 0

3 years ago

on his shelves trenton has 15 biogrophies,15 science fiction books,7 refrence books,and 11 mystery books. find the ratio of biog

weeeeeb [17]

The ratio of books is 15:48

6 0

3 years ago

The length of one side of a triangular lot is 6 m less than 3 times the length of the second side. The third side is 8 m longer

Tanya [424]

second side = x

first side = 3x - 6

third side = (3x - 6) + 8

The perimeter = 80m and is equal x + (3x - 6) + [(3x - 6) + 8]

x + 3x - 6 + 3x - 6 + 8 = 80

7x - 4 = 80 |+4

7x = 84 |:7

x = 12 m

3x - 6 = 3(12) - 6 = 30 m

(3x - 6) + 8 = 3x + 2 = 3(12) + 2 = 38 m

Answer: 12m, 30m, 38m

8 0

3 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

4 years ago

George has $15. He tries to buy a movie ticket ($9.00), a pretzel ($2.65), a drink ($1.35), and two veggie cups ($1.74 each) but

mezya [45]

Answer:

He doesn't have enough money because the total of things he wants to buy is more than the money he has.

Step-by-step explanation:

9 + 2.65 + 1.35 + 2(1.74) must be less than or equal to 15. However all of this added together equals $16.48. This means that he doesn't have enough money.

6 0

3 years ago

Read 2 more answers