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lidiya [134]
3 years ago
9

PLS HELP WILL MARK BRAINLIEST TO BEST ANSWER

Mathematics
2 answers:
butalik [34]3 years ago
6 0
I believe 504,000 seconds
OleMash [197]3 years ago
3 0

Answer

554,400 seconds is the answer

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a sandwich shop has 60 stores and 70 percent of the stores are I California. How many stores are in California and Nevada
Aliun [14]

Answer:

The number of stores in California 42

The number of stores in Nevada 18

Step-by-step explanation:

Given as :

The total sandwich shop in California and Nevada = 60

The percentage of shop in California = 70%

So, The percentage of shop in Nevada = 100% - 70% = 30%

Let The number of stores in California = c

And The number of stores in Nevada = n

Now, According to question

The number of stores in California = 70% of the total number of shops

I.e c = \frac{70}{100} ×  total number of shops

Or, c =  \frac{70}{100} × 60

∴   c = \frac{70\times 60}{100}

or, c =   \frac{4200}{100}

or, c = 42

So, The number of stores in California = c =42

Again

The number of stores in Nevada = 30% of the total number of shops

I.e n = \frac{30}{100} ×  total number of shops

Or, n =  \frac{30}{100} × 60

∴   n = \frac{30\times 60}{100}

or, n =   \frac{1800}{100}

or, n = 18

So, The number of stores in Nevada = n = 18

Hence The number of stores in California 42

And The number of stores in Nevada 18   Answer

8 0
3 years ago
Please help with this fast
Elena-2011 [213]

Answer:

Part 1) The value of x is 50°

Part 2) The measure of angle LOK is 114°

Option C

Step-by-step explanation:

we know that

if two angles are supplementary, then their sum is equal to 180 degrees

so

(x+64)°+66°=180°

solve for x

x+130°=180°

x=180°-130°=50°

Find the measure of angle LOK

∠LOK=(x+64)°

∠LOK=(50+64)°=114°

4 0
2 years ago
Help this is the last question to a test
goblinko [34]
You’re a Horrible Person
Solutions are given in alphabetical order (k, x, y, z)

[(1, 0, 0, 1), (1, 0, 1, 0), (1, 1, 0, 0), (2, 0, 1, 1), (2, 1, 0, 1), (2, 1, 1, 0), (3, 1, 1, 1), (8, 0, 0, 2), (8, 0, 2, 0), (8, 2, 0, 0), (9, 0, 1, 2), (9, 0, 2, 1), (9, 1, 0, 2), (9, 1, 2, 0), (9, 2, 0, 1), (9, 2, 1, 0), (10, 1, 1, 2), (10, 1, 2, 1), (10, 2, 1, 1), (16, 0, 2, 2), (16, 2, 0, 2), (16, 2, 2, 0), (17, 1, 2, 2), (17, 2, 1, 2), (17, 2, 2, 1), (24, 2, 2, 2), (27, 0, 0, 3), (27, 0, 3, 0), (27, 3, 0, 0), (28, 0, 1, 3), (28, 0, 3, 1), (28, 1, 0, 3), (28, 1, 3, 0), (28, 3, 0, 1), (28, 3, 1, 0), (29, 1, 1, 3), (29, 1, 3, 1), (29, 3, 1, 1), (35, 0, 2, 3), (35, 0, 3, 2), (35, 2, 0, 3), (35, 2, 3, 0), (35, 3, 0, 2), (35, 3, 2, 0), (36, 1, 2, 3), (36, 1, 3, 2), (36, 2, 1, 3), (36, 2, 3, 1), (36, 3, 1, 2), (36, 3, 2, 1), (43, 2, 2, 3), (43, 2, 3, 2), (43, 3, 2, 2), (54, 0, 3, 3), (54, 3, 0, 3), (54, 3, 3, 0), (55, 1, 3, 3), (55, 3, 1, 3), (55, 3, 3, 1), (62, 2, 3, 3), (62, 3, 2, 3), (62, 3, 3, 2), (64, 0, 0, 4), (64, 0, 4, 0), (64, 4, 0, 0), (65, 0, 1, 4), (65, 0, 4, 1), (65, 1, 0, 4), (65, 1, 4, 0), (65, 4, 0, 1), (65, 4, 1, 0), (66, 1, 1, 4), (66, 1, 4, 1), (66, 4, 1, 1), (72, 0, 2, 4), (72, 0, 4, 2), (72, 2, 0, 4), (72, 2, 4, 0), (72, 4, 0, 2), (72, 4, 2, 0), (73, 1, 2, 4), (73, 1, 4, 2), (73, 2, 1, 4), (73, 2, 4, 1), (73, 4, 1, 2), (73, 4, 2, 1), (80, 2, 2, 4), (80, 2, 4, 2), (80, 4, 2, 2), (81, 3, 3, 3), (91, 0, 3, 4), (91, 0, 4, 3), (91, 3, 0, 4), (91, 3, 4, 0), (91, 4, 0, 3), (91, 4, 3, 0), (92, 1, 3, 4), (92, 1, 4, 3), (92, 3, 1, 4), (92, 3, 4, 1), (92, 4, 1, 3), (92, 4, 3, 1), (99, 2, 3, 4), (99, 2, 4, 3), (99, 3, 2, 4), (99, 3, 4, 2), (99, 4, 2, 3), (99, 4, 3, 2)]
3 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
2 years ago
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