Answer: The running speed of Elena is 5 miles/hour and this can be determined by using the formula of speed.
Step-by-step explanation:
A circular running track 1/4 is a mile long.
Elena runs on this track, completing each lap in 1/20 of an hour.
Speed formula is used to determine the speed of Elena. The formula of speed is given by:
----- (1)
where S is the speed, D is the distance and T is the time taken by Elena to run a circle.
Now, put the value of distance D and time T in the equation (1).
Speed = 5 miles/hour
Therefore, the running speed of Elena is 5 miles/hour.
For more information, refer to the link given below:
brainly.com/question/22610586
I’m pretty sure it’s d because 2 is how much the cells have multiplied by hour say you started with 3 and it been three hours you would have 24 cells because it double the amount every time 3*2=6*2=12*2=24
The correct answer is: [B]: "40 yd² " .
_____________________________________________________
First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
_________________________________________________
Answer:
Length of Ladder(Hypotenuse)=18
Height of wall(Opposite) =14
How far from the base... This talks about the adjacent or distance between the wall and the base.
You can get your answer from Pythagoras theorem
Which states
The square of the hypotenuse is = to the squares of the adjacent and Opposite sides
H² = O² + A²
We're looking for the adjacent "A"
Making A the subject
A² = H² - O²
A= √H² - O²
A= √18² - 14²
A=√128
A= 8√2'