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3 years ago

Hello!!!!! help me for points

Mathematics

1 answer:

Klio2033 [76]3 years ago

7 0

I’m not sure how to do that but I just put something so I can get points

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Im doing a test review and I have no idea how to do this

Arisa [49]

Answer:

94.3?

Step-by-step explanation:

Well, the straight line is 180 degrees, there is a 90 degree square, and a 13 degree angle. So add them up and divide by three?

6 0

4 years ago

Help pls :) 10 points

Alexeev081 [22]

Answer:

sq root of 64 = 8, sq root of 81 = 9, 8 and 9

Step-by-step explanation:

Since Sq root of 64 = 8 and Sq root of 81 = 9 it is known that sq root of 66 is between 8 and 9

7 0

3 years ago

Find the volume for each figure and round to the nearest hundredth.

ivann1987 [24]

Answer:

9.V=480

10.V=25.1

11.V=377

12.V=160

13.V=179.6

14.V=452.4

Step-by-step explanation:

9.V=l*w*h

V=10*8*6

V=480

10.V=pi*1^2*8

V=8pi

V=25.1

11.V=1/3pi*6^2*10

V=1/3pi*36*10

V=1/3pi *360

V=120pi

V=377

12.V=l*w*h/3

V=10*8*6/3

V=480/3

V=160

13.V=4/3pi*3.5^3

V=4/3pi *42.875

V=171.5/3pi

V=179.6

14.V=2/3pi*6^3

V=2/3pi*216

V=432/3pi

V=144pi

V=452.4

3 0

3 years ago

3. Which side in ΔFED does AC in ΔABC correspond to?

Dahasolnce [82]

Answer:

step by step below

Step-by-step explanation:

3. AB --> EF (53°)

BC --> DE (37°)

AC --> DF (90°)

4. EF/AB = 8/4 = 2 (scale factor)

5. DE = 2 x CB = 6

6. FD = √6²+8² = √100 = 10

8 0

3 years ago

Fill in the blanks below to make a true statement. In a binomial experiment with n trials and probability of success p, if np (1

Sergeu [11.5K]

Answer:

$\mu_{x}=np$

$\sigma^2_{X}=np(1-p)$

Step-by-step explanation:

∵ When x is a random variable having distribution B(n, p), then for sufficiently large value of n, the following random variable has a standard normal distribution,

$\frac{x-\mu}{\sigma}\sim N(0,1)$

Where,

$\mu=np$

$\sigma^2=np(1-p)$

Here the variable X has a binomial distribution,

Such that, np (1 - p) ≥ 10 ⇒ n is sufficiently large.

Where, n is the total numbers of trials, p is success in each trials,

So, the mean of variable X is,

$\mu_{X} = np$

And, variance of variable X is,

$\sigma^2{X}=np(1-p)$

3 0

3 years ago