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2 years ago

Factor out the GCF of the polynomial down below:

Mathematics

1 answer:

Yuliya22 [10]2 years ago

7 0

Answer: 2x^3

Reasoning: balance out the numbers

Mark brainliest please

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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.

const2013 [10]

Answer:

$T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

Step-by-step explanation:

Remember that for any curve $r(t)$

The tangent vector is given by

$T(t) = \frac{r'(t) }{| r'(t)| }$

And the normal vector is given by

$N(t) = \frac{T'(t)}{|T'(t)|}$

For this case, using the chain rule

$r'(t) = ( -10*2tsin(t^2) , 102t cos(t^2) )\\$

And also remember that

$|r'(t)| = \sqrt{(-10*2tsin(t^2))^2 + ( 10*2t cos(t^2) )^2} \\\\ = \sqrt{400 t^2*( sin(t^2)^2 + cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t$

Therefore

$T(t) = r'(t) / |r'(t) | = ( -10*2tsin(t^2) , 10*2t cos(t^2) )/ 20t\\\\ = ( -10*2tsin(t^2)/ 20t , 10*2t cos(t^2) / 20t )\\= ( -sin(t^2), cos(t^2) )$

Similarly, using the quotient rule and the chain rule

$T'(t) = ( -2t cos(t^2) , -2t sin(t^2))$

And also

$|T'(t)| = \sqrt{ ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t$

Therefore

$N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

Notice that

1. $|N(t)| = |T(t) | = \sqrt{ cos(t^2)^2 + sin(t^2)^2 } = \sqrt{1} = 1$

2. $N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0$

Simlarly

$r'(t) = (2t,-6,0) \\$

and

$|r'(t)| = \sqrt{(2t)^2 + 6^2} = \sqrt{4t^2 + 36}$

Therefore

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

Then

$T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)$

and also

$|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 + ( (3 t)/(9 + t^2)^{3/2})^2 + 0^2 }\\= 3/(t^2 + 9 )$

And since

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

6 0

3 years ago

of the 80 guests invited to a wedding, 28 attended the wedding. What percent of the invited guests attended the wedding?

klasskru [66]

Answer:

35%

Step-by-step explanation:

% of guests who attended the wedding is number of guests who attended the wedding divided by the number of invited guests and the result multiplied by 100%

Therefore

28/80 x 100%

0.35 x 100%

35%

35% of the invited guests attended the wedding

4 0

3 years ago

Evaluate 12 (math).......

Diano4ka-milaya [45]

Evaluating Expressions Using Algebra Calculator

First go to the Algebra Calculator main page.

Type the following:

First type the expression 2x.Then type the @ symbol.Then type x=3.Try it now: 2x @ x=3

5 0

3 years ago

Help me decrease 25 by 30%

Marysya12 [62]

Step-by-step explanation:

Percentage decrease = 30% × 25

New value = 25 - Percentage decreaseNew value =

25 - Percentage decrease =

25 - (30% × 25) =

25 - 30% × 25 =

(1 - 30%) × 25 =

(100% - 30%) × 25 =

70% × 25 =

70 ÷ 100 × 25 =

70 × 25 ÷ 100 =

1,750 ÷ 100 =

17.5

Absolute change (actual difference) =

New value - 25 =

17.5 - 25 =

- 7.5

8 0

3 years ago

Read 2 more answers

The difference between 3.6 and a number is 2.95, as shown below. What number should go in the box to complete the subtraction pr

Sophie [7]

The missing number is 6. 3.6-.65 = 2.95
3.6 - 2.95 = .65

Hope it helps ;)))

8 0

3 years ago