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3 years ago

Find the distance from roller coaster 1 to the swings please help

Mathematics

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

Step-by-step explanation:

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An antenna is atop the roof of a 100 foot building, 10 feet from the the edge, as shown in the figure below. From a point 50 fee

Brut [27]

I think it must be the right triangle so
x=height of the antenna
tan(66)=x/50
x=50*tan(66)
x=1.33 ft
->the height of the antenna = 1.33 ft
hope it is the correct answer because you didn't provided me enough information.

3 0

3 years ago

An angle of 200 is a/an _______ angle.<br> a. reflex<br> b. straight<br> c. right<br> d. acute

krok68 [10]

Reflex angle because straight is 180 and right is 90 and acute is less than 90

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3 years ago

A plumber charges $90 per hour and a $50 travel fee.

Fittoniya [83]

Okay so subtract 50 from both sides and you would get 360=90x and then divide each side by 90 and you would get x= 4 so it took 4 hours

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4 years ago

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If a triangle has 2 60 degree angles, what kind of triangle is it?

alexira [117]

Answer:

equilateral

Step-by-step explanation:

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3 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

4 years ago