Answer:
A 46.1+(-97.2)
Step-by-step explanation:
Its the same as going 46.1 - 97.2 because your adding a negitive to a positive you canceling out the addition with the negitive so your now subtracting
First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at 
, the equation will contain a 
term.
If we start with 
we have a parabola, concave down, with vertex at and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have
Now we only have to fix the fact that this parabola doesn't land at 
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
such that:
Plugging these values gets us
As you can see in the attached figure, the parabola we get satisfies all the requests.
It's the same angle. The equation, then, is 5y+1=51. Subtract one from both sides, so now you've got 5y=50. Divide each side by 5 and you've got y=10.
Answer:
Triangles QUT and SVR are congruent because the defining two sides and an included angle of triangles QUT and SVR are equal
Step-by-step explanation:
Here we have QT = SR and
QV = SU
Therefore,
QT = √(UT² + QU²)........(1)
RS = √(VS² + RV²)..........(2)
Since QS = QU + SU = QV + VS ∴ QU = VS
Therefore, since SR = QT and QU = VS, then from (1) and (2), we have UT = RV
Hence since we know all sides of the triangles QUT and SVR are equal and we know that the angle in between two congruent sides of the the triangles QUT and SVR that is the angle in between sides QU and UT for triangle QUT and the angle in between the sides RV and VS in triangle SVR are both equal to 90°, therefore triangles QUT and SVR are congruent.
Answer:
(5)2
Step-by-step explanation:
As we know that the equation of circle with center at (h,k) ad radius r is given as-
(x−h)
2
+(y−k)
2
=r
2
Given that the centre of circle is (1,4) and radius is 5.
Therefore the equation of circle is-
(x−1)
2
+(y−4)
2
=(5)
2
, we have
