Question

What is the equation of a line perpendicular to y= 3/4x +12 that passes through (12, 3)

Answer 1

Answer:

y=-4/3x-9

 

=

−

4

3

x

−

9

Step-by-step explanation:

First we need to get the slope of the perpendicular line

The slope of a perpendicular line is equal to the negative inverse of the slope of the given line

y

=

m

x

+

b

y

=

3

4

x

−

2

⇒

m

=

3

4

m

'

=

−

1

m

⇒

m

'

=

−

1

3

4

⇒

m

'

=

−

4

3

Now that we have the slope, we need to find the y-intercept.

To find the y-intercept, we need to plug-in values of  

x

and  

y

that the line passes through

y

'

=

m

'

x

'

+

b

⇒

y

'

=

−

4

3

x

'

+

b

⇒

7

=

−

4

3

(

−

12

)

+

b

⇒

7

=

16

+

b

⇒

b

=

−

9

Therefore, the equation of the line is

y

=

−

4

3

x

−

9