1.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that reacts with water to produce a lilac flame
2.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element used as an inert atmosphere
3.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element that has a valency of 3
4.Write a balanced chemical equation for the reaction between potassium and water. (Non-anonymous question). .
(1 Point)
Upload file
File number limit: 1Single file size limit: 10MBAllowed file types: Word, Excel, PPT, PDF, Image, Video, Audio
5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2
HELP
<span> -14x + 11y = 23
+2(7x - 3y = 37)
----------------------
0 + 5y = 97
y = 97/5
y = 19.4
7x - 3(19.4) = 37
7x - 58.2 = 37
7x = 37 + 58.2
7x = 95.2
x = 95.2/7
x = 13.6
Check
-14(13.6) + 11(19.4) = 23
-190.4 + 213.4 = 23
</span>
Answer:
D) 1188 in.^2
Step-by-step explanation:
33×36 is 1188, the triangle on the side doesn't matter because it can be used to make the rectangle a whole rectangle, which means that the only important numbers are 33 and 36 multiplied to find the area, which is 1188^2.
Answer:
The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.
Answer:
35 different routes
Step-by-step explanation:
The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.
Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.
The number of combinations of n objects taken r at a time is: ⁿCᵣ
So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by
⁷C₄ = 35 different ways.
Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.
Hope this Helps!!!