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RoseWind [281]
3 years ago
9

The graph shows the carrying capacities for two populations of salmon in two different areas which statement is most likely true

of area

Biology
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

Area A has more food resources than area B.

Explanation:

Carrying capacity refers to the maximum population size that a habitat can support as per its available resources such as food, space etc. According to the given graph, the carrying capacity of area "A" is higher than that of area "B" since area "A" supports larger population size of salmon than area B. The higher carrying capacity of area A could be due to presence of more food resources in the region to support the larger population size.

nika2105 [10]3 years ago
6 0

The most likely answer is that there is more food in salmon A location

Hope this helps!

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Identify the phenotypes for the offspring of a parent with the genotype IBi and a parent with the genotype IAIA. type O type A,
agasfer [191]
 <span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant. 

O is always ii 
A is IAi (heterozygous) or IAIA (homozygous) 
B is IBi (heterozygous) or IBIB (homozygous) 
AB is always IAIB 

Remember: You get one allele from each parent! 

1. Father must be ii, mother must be ii, so all children must be ii. 

2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother. 

3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes. 

4. Father is ii, mother is IAIB. Children can only be IAi or IBi. 

5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB. 

Example of Punnett square: 
3. Father is type A, heterozygous, mother is type B, heterozygous 
Father must be IAi (heterozygous) 
Mother must be IBi (heterozygous) 

_______IA ____ i 

IB____ IBIA____IBi 

i _____ IAi______ii 

Sorry, that was difficult on here, hope it's understandable. 
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case. 

Hope that helps!</span>
6 0
3 years ago
Are my answers correct for Q1??
sertanlavr [38]

You're correct.

Just make the last one OO

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