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3 years ago

By how much is 7029 more than 3029?

Mathematics

1 answer:

Alex Ar [27]3 years ago

7 0

4000 bro
Explanation: just subtract 3029 from 7029

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3 years ago

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Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

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3 years ago

Help me with my math for brainiest:)

MissTica

Answers:
1. P=3

Step by step:
P-5=-2 -move the constant to the right hand side and change its sign

P=-2+5 - calculate the sum

P=3

2. W=-2.8

Step by step:
W+13.2=10.4 - move the constant tot he right hand side and change its sign

W=10.4-13.3 - calculate the difference

W=-2.8

3. X=2/3

Step by step:
X-5/6=-1/6 - move the constant to the rig hand side and change its sign

X=-1/6+5/6 - calculate the sum

X=2/3

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4 years ago

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