How do you find out and solve the problem to y=1.08

Write the vertex form of the equation of the parabola that has a vertex of (-6,-5) and passes through the point (-8,6)

Anastaziya [24]

Answer:

Step-by-step explanation:

Find the parabola through ( − 8 , 6 ) with vertex ( − 6 , -5 ) .

Standard Form: y = − 11 /4x ²− 44 x − 170

Vertex Form: y = − 11 /4 ( x + 8 ) 2 + 6

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7 0

3 years ago

Given the figure below, find the values of x and z .

harina [27]

Answer:

In the pic

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)

4 0

4 years ago

Use the diagram shown. There are two lines which intersect each other and making angles 1 and 2. The opposite angles to 1 is 3,

Rufina [12.5K]

Answer:

I think that A, B, and C are correct.

Step-by-step explanation:

1. Since measures 2 and 3 are a linear pair, they equal 180 degrees. A is correct.

2. Since measures 3 and 4 are also a linear pair, they too equal 180 degrees. B is correct.

3. Measures 2 and 3 are already established to be 180 degrees (check answer 1) , and measures 3 and 4 are also 180 degrees (check answer 2). Since they are both 180 degrees, they are congruent (equal), so C is correct.

D is NOT correct. Measures 1 and 3 are equal because they are vertical angles. We also know that they are acute angles (less than 90) so adding them together will equal less than 180 degrees.

Measures 2 and 4 are equal because they are vertical angles, and they are obtuse (more than 90 degrees). Adding them together will equal more than 180 degrees.

Logic tells us that something less than 180 CANNOT be equal to something more than 180. This proves that 2 and 4 and 1 and 3 are not congruent.

D is WRONG

8 0

2 years ago

Mark all statements that are true. Picture below.

Burka [1]

Answer:

Option A and D

Step-by-step explanation:

Step 1: Determine which options are true

Option A is correct because the range is always 3, the graph never moves.

Option B is incorrect because into order to be a function, there has to be only one y per x. Not one x per y.

Option C is incorrect because this line only stays at 3.

Option D is correct because the domain goes both to positive infinity and negative infinity.

Option E is incorrect because the domain is all real numbers.

Answer: Option A and D

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

3 years ago