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disa [49]
3 years ago
13

How do you find out and solve the problem to y=1.08

Mathematics
2 answers:
maksim [4K]3 years ago
8 0
You simply substitute, for example, if you have this problem
N+Y-3 x 2 = ? For N=6 and Y=7, solve.

You would substitute.
6+7-3 x 2
6+7-6
13-6
7
All you do is substitute the letter for what the problem says it it equals. I hope this makes sense:)
Anni [7]3 years ago
5 0
You have to be a bit more specific than that
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Which polynomial represents the sum below?<br> (3x2 + 3) + (3x2 + x + 4)
DIA [1.3K]
Add like terms just like you would anywhere else...6 x^{2} +x+7
6 0
3 years ago
The kinetic energy (K) that an object has varies jointly with its mass (m) and the square of its velocity (v). The equation that
lord [1]

The kinetic energy of the bowling ball with the mass and traveling at the given velocity is 10.14 Joules.

<h3>What is Kinetic Energy?</h3>

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Given that;

  • Mass of the bowling ball m = 3kg
  • Velocity of the bowling ball v = 2.6m/s
  • Kinetic energy K = ?

We substitute the given values into the above equation.

K = (1/2)mv²

K = 0.5 × 3kg × (2.6m/s)²

K = 0.5 × 3kg × 6.76m²/s²

K = 10.14kgm²/s²

K = 10.14J

Therefore, the kinetic energy of the bowling ball with the mass and traveling at the given velocity is 10.14 Joules.

Learn more about kinetic energy here: brainly.com/question/12669551

#SPJ1

6 0
2 years ago
6. Lamont keeps track of his math grades by recording them
zaharov [31]

Answer:

a

Step-by-step explanation:

drhhgfruuutrruiuhhhjjjjj*iuuuuu77887

7 0
3 years ago
What statement statement is not true is not true
Black_prince [1.1K]
C is the answer because with this kind of math the answer can be Neg or Postive <span />
5 0
3 years ago
The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each
Fynjy0 [20]

Answer:

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Step-by-step explanation:

Given equation of ellipsoids,

u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}

The vector normal to the given equation of ellipsoid will be given by

\vec{n}\ =\textrm{gradient of u}

            =\bigtriangledown u

           

=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})

           

=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}

           

=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}

Hence, the unit normal vector can be given by,

\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}

             =\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}

             

=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Hence, the unit vector normal to each point of the given ellipsoid surface is

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

3 0
3 years ago
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