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disa [49]
3 years ago
13

How do you find out and solve the problem to y=1.08

Mathematics
2 answers:
maksim [4K]3 years ago
8 0
You simply substitute, for example, if you have this problem
N+Y-3 x 2 = ? For N=6 and Y=7, solve.

You would substitute.
6+7-3 x 2
6+7-6
13-6
7
All you do is substitute the letter for what the problem says it it equals. I hope this makes sense:)
Anni [7]3 years ago
5 0
You have to be a bit more specific than that
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Which one is the correct answer?
KatRina [158]

\large \sf \pmb{D) \:  \frac{3n}{2}  + 5 \geqslant  - 12  }\\

  • Three time the quotient of a number and 2 increased by 5 is at most -12.
3 0
2 years ago
Read 2 more answers
The spinner shown is spun once. Find the probability of each event. Write each answer as a fraction, percent, and decimal. Ma
poizon [28]

Complete question :

The spinner shown is spun once. Determine the probability of each event. Express each answer as a fraction, a decimal, and a percent. P(C)

Answer:

1 / 8; 0.125 ; 12.5%

Step-by-step explanation:

From the spinner :

The number of partitions or faces on the spinner is 8 ;

The number of occurences of c on the spinner is 1

The probability of obtaining c written as P(c) :

Probability = required outcome = number of c on spinner / total possible outcomes, total number of faces in spinner = 8

P(c) = 1 / 8

As decimal :

1/8 = 0.125

As a percentage :

0.125 * 100% = 12.5%

7 0
3 years ago
Can you please help me?
Alexandra [31]

Answer:

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Step-by-step explanation:

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6 0
2 years ago
Find the 10th term of the geometric sequence 1, 3, 9, ...
ladessa [460]

Answer:

a(10) = 3^9 = 19683

Step-by-step explanation:

In this sequence each new term is equal to 3 times the previous term.  Thus, 3 is the common ratio.  The first term is 1.

The general formula for the nth term of a geometric sequence i

a(n) = a(1)*r^(n -1), where r is the common ratio.

Here, a(n) = 1*3^(n - 1), and so

the 10th term is

           a(10) = 1*3^(10 - 1), or

            a(10) = 3^9 = 19683

3 0
2 years ago
Please Help asap . picture attach
FinnZ [79.3K]
Answer: B) 0 real roots

---------------------------------------

The general rule is...
if D > 0, then you have two different real roots (see note below)
If D = 0, then you have exactly one real root 
If D < 0, then you have no real roots (the two roots are imaginary/complex)
where D is the discriminant found by the formula 
D = b^2 - 4ac

Note: If D is also a perfect square, then the two real roots are also rational. This assuming that a,b,c are rational. 
6 0
3 years ago
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