Defined as a phenomenon of liberation of electron from the surface that is stimulated by temperature elevation, radiation, or by strong electric field.
Answer:
0.0500L of 3.00M HCl are needed to react completely
Explanation:
Hydrochloric acid HCl reacts with sodium carbonate, Na2CO3, as follows:
2HCl + Na₂CO₃ → 2NaCl + H₂O + CO₂
<em>Where 2 moles of HCl reacts per mole of Na₂CO₃</em>
<em />
To find the volume of 3.00M HCl needed to react completely we need first to calculate the moles of Na₂CO₃ added and, with this chemical equation we can solve for moles of HCl as follows:
<em>Moles Na₂CO₃:</em>
0.750L * (0.100moles Na₂CO₃ / L) = 0.0750moles
<em>Moles HCl:</em>
0.0750moles Na₂CO₃ * (2 moles HCl / 1 mole of Na₂CO₃) = 0.150 moles of HCl
<em>Volume of 3.00M HCl:</em>
0.150 moles of HCl * (1L / 3.00moles) =
<h3>0.0500L of 3.00M HCl are needed to react completely</h3>
Answer: Equilibrium concentration of 
= 0.00006 M
equilibrium concentration of 
= 0.00006 M
and equilibrium concentration of 
= 0.00064 M
Explanation:
Initial moles of = 0.0019 mole
Volume of container = 5.0 L
Initial concentration of 
initial concentration of 
The chemical reaction for the decomposition of phosgene follows the equation:
Initial conc. 0.00038 M 0.00038 M 0
At eqm. conc. ( 0.00038-x) M (0.00038-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[IBr]^2}{[I_2]\times [Br_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BIBr%5D%5E2%7D%7B%5BI_2%5D%5Ctimes%20%5BBr_2%5D%7D)
![108=\frac{[2x]^2}{(0.00038-x)^2}](https://tex.z-dn.net/?f=108%3D%5Cfrac%7B%5B2x%5D%5E2%7D%7B%280.00038-x%29%5E2%7D)
Thus equilibrium concentration of = (0.00038-x) M =(0.00038-0.00032) M = 0.00006 M
equilibrium concentration of = (0.00038-x) M =(0.00038-0.00032) M = 0.00006 M
equilibrium concentration of = 2x M = 2(0.00032) M=0.00064 M
Answer:
.4401
Explanation:
bc the formula for the mass is density × volume
