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3 years ago

If you were to add a proton to a neutral atom what would change

1 answer:

8 0

It would change the charge, a neutral atom has zero charge but a proton has a positive charge. So 0 charge + 1 positive charge = 1 positive charge.

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A 15.00g solid mixture containing Ca(OH)2, among other non-basic components, was neutralized with 0.2000g of HCl. What was the m

azamat

Answer:

1.373 wt% Ca(OH)₂

Explanation:

Sample mix = 15.0g

Ca(OH)₂(aq) + 2HCl(aq) => CaCl₂(aq) + 2H₂O(l)

moles HCl = 0.2000g / 36 g·mol⁻¹ 0.0056 mol

moles Ca(OH)₂ = 1/2(moles HCl) = 1/2(0.0056 mol) = 0.0028 mol

mass Ca(OH)₂ = 0.0028 mol ( 74 g/mol ) = 0.206 g

mass % Ca(OH)₂ = (0.206/15.0)100% = 1.373 wt%

3 0

3 years ago

What is the si unit for the quantity of particles in a sample?

kaheart [24]

The SI unit for the amount or quantity of small particles in a sample is referred to as the mole.

This tells how much in terms of atoms or molecules are present for a particular mass.

7 0

3 years ago

Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g

Tema [17]

<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Given mass of oxygen = 50 g

Molar mass of oxygen = 32.00 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen}=\frac{50g}{32g/mol}=1.5625mol$

For the given chemical equation:

$2H_2O\rightarrow 2H_2+O_2$

By Stoichiometry of the reaction:

1 mole of oxygen is produced when 2 moles of water is reacted.

So, 1.5625 moles of oxygen is produced when = $\frac{2}{1}\times 1.5625=3.125mol$ of water is reacted.

To calculate the mass of water, we use equation 1:

Moles of water = 3.125 moles

Molar mass of water = 18.01 g/mol

Putting values in equation 1, we get:

$3.125mol=\frac{\text{Mass of water}}{18.01g/mol}\\\\\text{Mass of water}=56.28g$

Hence, the mass of water that must be reacted is 56.28 grams.

3 0

4 years ago

Please answer this thanks!!...

Alex17521 [72]

Answer:sorry.

Explanation:

4 0

3 years ago

If the temperature of 68.8 g of ethanol increases from 40.0(C to 71.3(C, how much heat has been absorbed by the ethanol? (Specif

ale4655 [162]

Answer:

Q = 5254.39 J

Explanation:

Given that,

Mass of ethanol, m = 68.8 g

The temperature increases from 40.0°C to 71.3°C.

The specific heat of ethanol is 2.44 j/g°C

We need to find the heat absorbed by the ethanol. We know that the heat absorbed due to the change in temperature is given by :

$Q=mc\Delta T$

Put all the values,

$Q=68.8\times 2.44\times (71.3-40)\\\\Q=5254.39\ J$

So, 5254.39 J of heat is absorbed by Ethanol.

3 0

3 years ago