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2 years ago

Simplify 3x -5 + 25x-9

Mathematics

2 answers:

Gemiola [76]2 years ago

6 0

Always remeber to put like terms together.
3x + 25x - 5 - 9 = 28x - 14
Hope this helps ;)

mash [69]2 years ago

3 0

Answer:

28x - 14

Step-by-step explanation:

3x - 5 + 25x - 9

= 28x - 14

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Which statements about countries with lower GDP and lowest HDI scores are accurate? Check all that apply

yKpoI14uk [10]

Answer:The countries with lower GDP are the same as those with the lowest HDI.

U GDP is a solid indicator of what a country's HDI will be.

da

Step-by-step explanation:

Which statements about countries with lower GDP and lowest HDI scores are accurate?

The countries with lower GDP are the same as those with the lowest HDI - human development index a measure of life expectancy, education and per capita income indicators.

The GDP rank tends to be associated with the lowest HDI.

U GDP - gross domestic product the total monetary value of goods and services in country at a specific time period is a solid indicator of what a country's HDI will be.

The GDP can be used to rank a country's HDI

6 0

2 years ago

Read 2 more answers

I have no idea what im doing

omeli [17]

Answer:

x = - 6

Step-by-step explanation:

A hole is an input value that makes both numerator and denominator equal to zero.

<u>Let's factorize the numerator and denominator:</u>

3x² - 108 = 3(x² - 36) = 3(x + 6)(x - 6)
x² + 2x - 24 = x² + 6x - 4x - 24 = x(x + 6) - 4(x + 6) = (x - 4)(x + 6)

<u>We have same factor of x + 6:</u>

x + 6 = 0
x = - 6 is a hole

8 0

2 years ago

Find the x intercept for the graph, 3x-14y+12=0

melamori03 [73]

The x-intercept would be (-4,0)

4 0

2 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

A woman jogs for 2 km at 8 km/h and then walks for 2 km

Artemon [7]

Answer:

6 6/7 km/h

Step-by-step explanation:

The relations between speed, time, and distance are ...

time = distance/speed

speed = distance/time

So, to find the average speed, we need to know the total distance and the total time. The distances are given, but we need to compute the times.

time jogging = (2 km)/(8 km/h) = 1/4 h

time walking = (2 km)/(6 km/h) = 1/3 h

Then the woman's average speed is ...

average speed = (total distance)/(total time) = (2 km + 2 km)/(1/4 h + 1/3 h)

= (4 km)/(7/12 h) = 48/7 km/h

= 6 6/7 km/h

3 0

2 years ago