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Ghella [55]
3 years ago
8

Graph the inequality on a number line. s < 1 1/2

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
5 0

Step-by-step explanation:

Put a open circle at 1 1/2 then draw a line going to the left of 1 1/2

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I think it is graph letter c
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3 2/5 time 5. Show work
xenn [34]

let's firstly convert the mixed fraction to improper fraction and then multiply.

\bf \stackrel{mixed}{3\frac{2}{5}}\implies \cfrac{3\cdot 5+2}{5}\implies \stackrel{improper}{\cfrac{17}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{17}{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\implies 17

8 0
3 years ago
PLEASE HELP! Find the missing part.
viktelen [127]

Answer:

Step-by-step explanation:

\frac{y}{a}= tan~60=\sqrt{3} \\y=a\sqrt{3} ~~~(1)\\\frac{y}{b} =tan~30\\y=\frac{b}{\sqrt{3} } ~~~(2)\\from~(1)~and~(2)\\a\sqrt{3} =\frac{b}{\sqrt{3} } \\b=a\sqrt{3} \times\sqrt{3} =3a\\a+b=15\\a+3a=15\\4a=15\\a=\frac{15}{4} \\b=3a=3 \times \frac{15}{4} =\frac{45}{4}\\y=a\sqrt{3} =\frac{15\sqrt{3}}{4} \\\frac{x}{15} =sin~30\\x=15 \times \frac{1}{2}=\frac{15}{2}\\\frac{z}{15}=cos~30\\z=15 \times \frac{\sqrt{3}}{2}=\frac{15\sqrt{3} }{2} \\

4 0
3 years ago
The area of the trapezoid
ELEN [110]

Answer:

<h2>A = 82.5 in²</h2>

Step-by-step explanation:

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

b₁, b₂ - bases

h - height

We have b₁ = 10in, b₂ = 5in and h = 11in. Substitute:

A=\dfrac{10+5}{2}\cdot11=\dfrac{15}{2}\cdot11=7.5\cdot11=82.5\ in^2

7 0
4 years ago
Read 2 more answers
A boat on a river travels downstream between two points, 20 mi apart, in one hour. The return trip against the current takes 2 1
kondaur [170]

Answer:

The speed of boat in still water is 14 miles per hour.

The speed of current is 6 miles per hour.

Step-by-step explanation:

Let v represent the speed of boat in still water and c represent speed of current.

We have been given that a boat on a river travels downstream between two points, 20 miles apart, in one hour.

The speed of boat downstream would speed of boat in still water plus speed of current that is (v+c).

The return trip against the current takes 2 1/ 2 hours. The speed of boat against current would speed of boat in still water minus speed of current that is (v-c).

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Substituting our given values, we will get:

v+c=\frac{20}{1}...(1)

v-c=\frac{20}{2.5}...(2)

Adding both equations, we will get:

v+c+(v-c)=\frac{20}{1}+\frac{20}{2.5}

v+c+v-c=\frac{20}{1}+\frac{20}{2.5}

2v=20+8

2v=28

\frac{2v}{2}=\frac{28}{2}

v=14

Therefore, the speed of boat in still water is 14 miles per hour.

To find the speed of the current in the river, we will substitute v=14 in equation (1) as:

14+c=\frac{20}{1}

14+c=20

14-14+c=20-14

c=6

Therefore, the speed of current is 6 miles per hour.

3 0
3 years ago
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