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dusya [7]
3 years ago
7

Write an equation for a circle with a radius of 3 and a center located at point (2,-1)

Mathematics
1 answer:
jeyben [28]3 years ago
4 0

Answer:

(x - 2)^2  + (y + 1)^2 = 9

Step-by-step explanation:

recall the equation for a circle:

(x - h)^2 +  (y - k)^2 = r^2

here (h, k) = (2, -1)

and r = 3

so

(x - 2)^2  + (y -(-1))^2 = 3^2

(x - 2)^2  + (y + 1)^2 = 3^2

(x - 2)^2  + (y + 1)^2 = 9

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Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expect
Amanda [17]
P(8 or 12) = 1/6
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E(X)=9\times\frac{1}{6}-2\times\frac{5}{6}=-\frac{1}{6}\ points
The answer is -(1/6) points.
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2 years ago
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X + 19 + 7x + 9 = 180
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Answer:

<u>C. 1 to 7.99</u>

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Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe
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3 years ago
Let W be the subspace of R5 spanned by the vectors w1, w2, w3, w4, w5, where
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To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors. 

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<span>p(u,v)=u*(u.v)/(u.u) </span>
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<span>u1=w1 </span>
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<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
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<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>

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