Given:
The function is

To find:
The correct ordered pairs.
Solution:
We have,

For x=3,


So, the ordered pair is
.
For x=-2,

![[\because (\dfrac{a}{b})^{-n}=(\dfrac{b}{a})^n]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28%5Cdfrac%7Ba%7D%7Bb%7D%29%5E%7B-n%7D%3D%28%5Cdfrac%7Bb%7D%7Ba%7D%29%5En%5D)

So, the ordered pair is
.
For x=1,


So, the ordered pair is
.
For x=-1,

![[\because (\dfrac{a}{b})^{-n}=(\dfrac{b}{a})^n]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28%5Cdfrac%7Ba%7D%7Bb%7D%29%5E%7B-n%7D%3D%28%5Cdfrac%7Bb%7D%7Ba%7D%29%5En%5D)

So, the ordered pair is (-1,5). This is the correct answer.
Therefore, the correct option is D.
Hello,
There are 4 congurent equilateral triangles in ABC and each has an area of (8/5)/4=2/5.
To form the parallelogram we need 2 triangles: 2* 4/5=4/5.
Answer C.
Answer:
- 1296 pounds per square inch
Step-by-step explanation:
<u>Direct variation equation:</u>
<u>In this case it is:</u>
- y = kx², where y- strength, x- depth of the beam, k- coefficient
<u>Substitute the given values and solve for k:</u>
- 3600 = k*10²
- 3600 = 100k
- k = 3600/100
- k = 36
<u>The equation becomes:</u>
<u>Now, find the value of y, when x is 6:</u>
<u><em>Note, I took the depth as 6 inches but the question is a bit confusing by saying "four six inches". If it is 4 inches then your answer will be:</em></u>
Answer:
Length of the hypotenuse = 23.43ft
Step-by-step explanation:
First leg = 15ft
Second leg = 18ft
Length of the hypotenuse = ?
In a right angle triangle,
Hypotenuse^2 = opposite^2 + Adjacent^2
Let first leg and second leg of the triangle be opposite and adjacent respectively
Hypotenuse^2 = opposite^2 + Adjacent^2
= 15^2 + 18^2
= 225 + 324
= 549
Hypotenuse^2 = 549
Find the square root of both sides
√Hypotenuse^2 = 549
Hypotenuse = 23.43ft to the nearest of a hundredth
Length of the hypotenuse = 23.43ft
Answer:
a) we have the numbers 0, 2, 3, 5, 5. The mean and the median are both 3
b) we have the numbers 0, 0, 3, 5, 7. The mean and the median are both 3
In both cases the mean and the median are 3, but the mode differs. The mean and the median do not uniquely determine the mode.
Step-by-step explanation: