In which quadrant would point (-4.5, -4.5) be located

Someone help me please!

Vilka [71]

Answer:

$50 \leq x \leq 350\\$

Step-by-step explanation:

6 0

3 years ago

In triangle STU, u2 = s2 + t2.

sineoko [7]

Answer:

(B) The measure of angle SUT is equal to 90 degrees

Step-by-step explanation:

It is given that in In triangle STU, $u^2=s^2+t^2$ .

We can see from the triangle and also the given condition that the triangle will be right triangle as it is satisfying the Pythagoras theorem.

$(Hyp)^2=(Base)^2+(Perpendicular)^2$

that is:

$u^{2}=s^{2}+t^{2}$

where u is the hypotenuse, s is the base and t is the perpendicular.

Thus, the angle SUT should be of 90°.

Thus, The measure of angle SUT is equal to 90 degrees.

Hence, option B is correct.

3 0

3 years ago

Can you do this 4 me

VikaD [51]

Answer:

punany because the circular circumstances say that it is correct

Step-by-step explanation:

6 0

3 years ago

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

3 years ago

What’s the answer?!!

Grace [21]

Answer:

6x+10mm=p is the answer

brainlest plz

6 0

3 years ago