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Marrrta [24]
2 years ago
5

Solve for r literal equation

\frac{a}{a-r}" alt="S = \frac{a}{a-r}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ivanzaharov [21]2 years ago
8 0

Step-by-step explanation:

s =  \frac{a}{a - r}

multiply both sides by a - r

(a - r)s = a

divide both sides by s

a - r =  \frac{a}{s}

subtract a from both sides

- r =  \frac{a}{s}  - a

invert the signs

r =  -  \frac{a}{s}  + a

You might be interested in
The quotient of two numbers is 17, and their sum is 36. what are the two numbers?
Naddika [18.5K]
Let, the numbers = a, b

a/b = 17
a = 17b

& a + b = 36
17b + b = 36
18b = 36
b = 36/18
b = 2

So, a = 17(2) = 34

In short, Your Numbers would be: 2 & 34

Hope this helps!
7 0
3 years ago
How do I solve this?
Fofino [41]
....... The answer is: x=1
7 0
4 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) t
solniwko [45]

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean \bar x =  371.08

standard deviation \sigma = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = \dfrac{\sigma }{\sqrt{n}}

Standard Error S.E = \dfrac{24.45 }{\sqrt{26}}

Standard Error S.E = \dfrac{24.45 }{4.898979486}

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  \approx 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = \sigma \times \sqrt{1+ \dfrac{1}{n}}

The standard error of the mean = 24.45 \times \sqrt{1+ \dfrac{1}{26}}

The standard error of the mean = 24.45 \times \sqrt{1+0.03846153846}

The standard error of the mean = 24.45 \times \sqrt{1.03846153846}

The standard error of the mean = 24.45 \times 1.019049331

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

\approx 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

8 0
4 years ago
Please help!!!!!!!!!!!!!
Vadim26 [7]

the square root of 121, because when rationalized its 11.

7 0
3 years ago
Read 2 more answers
Please help! When divided by 30, which numbers have a remainder? Select three options.
-Dominant- [34]

Answer:

200, 400, 500, 800

Step-by-step explanation:

sorry, I put 4 options instead of three

8 0
3 years ago
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