The missing number is 20
<h3>How to determine the number</h3>
We can see that the values at the top must be made equal to that at the bottom
For the top, we have
30 + 11 = 41
For the bottom, we should have:
21 + x = 41
Now, let's solve for 'x' to determine the missing figure;
21 + x = 41
collect like terms
x = 41 - 21
x = 20
Thus, the missing number is 20
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Answer:
Isolate the variable by dividing each side by factors that don't contain the variable
Exact Form:
x = - 25/8 
Decimal Form:
x = -3.125
Mixed Number Form:
x = - 3/1/8
Step-by-step explanation:
Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
Answer: At most 3
Step-by-step explanation:
If there are 25 white socks and 25 red socks, a matching pair would be picked in at most 3 times.
The first sock you pick would be either White or Red
The second sock you pick would be either white or red again which means that you now either have 2 whites, 2 reds or 1 white and 1 red.
The third sock you pick will either be white or red once more. At this point you will either have 3 whites, 3 reds, 2 whites and 1 red or 2 reds and 1 white.
You will therefore have at least a matching pair after 3 tries.
A. True. We see this by taking the highest order term in each factor:
B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.
C. False. f(x) = 0 only for x=0, x = 5, and x = -2.
D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.
E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).
F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.
