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madam [21]
3 years ago
8

Solve the equation x+3/x-4 = x-5/x+4

Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:

\large\boxed{x=\dfrac{1}{2}}

Step-by-step explanation:

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\\\\\text{Domain:}\ x-4\neq0\ \wedge\ x+4\neq0\\\\x\neq4\ \wedge\ x\neq-4\\\\D:x\in\mathbb{R}-\{-4,\ 4\}

\dfrac{x+3}{x-4}=\dfrac{x-5}{x+4}\qquad\text{cross multiply}\\\\(x+3)(x+4)=(x-4)(x-5)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x)(x)+(x)(4)+(3)(x)+(3)(4)=(x)(x)+(x)(-5)+(-4)(x)+(-4)(-5)\\\\x^2+4x+3x+12=x^2-5x-4x+20\qquad\text{combine like terms}\\\\x^2+(4x+3x)+12=x^2+(-5x-4x)+20\\\\x^2+7x+12=x^2-9x+20\qquad\text{subtract}\ x^2\ \text{from both sides}\\\\7x+12=-9x+20\qquad\text{subtract 12 from both sides}\\\\7x=-9x+8\qquad\text{add}\ 9x\ \text{to both sides}\\\\16x=8\qquad\text{divide both sides by 16}\\\\x=\dfrac{8}{16}\\\\x=\dfrac{8:8}{16:8}\\\\x=\dfrac{1}{2}\in D

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Answer:

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Step-by-step explanation:

A = 84 feet square

ratio of length and width = 7 : 3

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width = (3/10)a

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8 0
3 years ago
One base of a trapezoid is five times as long as the other. The height is the average of the two bases. The area is 441 square u
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Answer:

The length of the longer base he 35 units

Step-by-step explanation:

Here, we want to find the length of the longer base of the trapezoid

Mathematically, we can find the area using the formula;

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where a is the shorter base

b is the longer base

h is the height

Let the shorter base be x

The other base is 5 times this length and that makes 5 * x = 5x

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Substituting these in the formula, we have ;

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3 years ago
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