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Free_Kalibri [48]
3 years ago
6

5-6x+8x² divided x-1​

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

4+2x

Check attached file for steps :)

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Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

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Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

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It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
A battery with
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