Ask question

Ask question

All categories

4 years ago

14

Using differentiation from first principles, prove that the gradient of the line y=mx + c is m

1 answer:

adell [148]4 years ago

3 0

$\frac{dy}{dx} = m$
because when you differentiate, only the constant of the x remains (which is m in this case), and c being another constant independent of x, is 0 when differentiated. hence, since dy/dx is the gradient of the line, m is therefore the gradient

You might be interested in

Use a graphing utility to approximate (to two decimal places) any relative

iogann1982 [59]

Answer:

Relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and relative maxima DNE.

Step-by-step explanation:

The given function is f(x) = x (x + 7) ...... (1)

We have to calculate the relative maxima and relative minima at point (x, y).

Rearranging the function given above we get.

$y= x^{2} +7x = (x + \frac{7}{2} )^{2} -\frac{49}{4}$

⇒ $y+ \frac{49}{4} = (x + \frac{7}{2} )^{2}$

Now, this is an equation of parabola having vertex at $(-\frac{7}{2} , -\frac{49}{4} )$ and the axis is parallel to positive Y-axis.

Therefore, the function(1) has a relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and the relative maxima DNE. (Answer)

3 0

3 years ago

Help me please I don’t know what to do what’s the answer

shtirl [24]

YAY!!! ANOTHER PERSON FRON ED-GENUITY!!!
All of the letters are equal to 90 degrees so the answer would be C.
Hope I helped!

7 0

3 years ago

Find the volume of the solid. Round to the nearest tenth if necessary.

Vikki [24]

$V= \frac{4}{3} \pi r^{3} or V=4.1888 r^{3}$

r=4 $r^{3}$ =64*4.1888=268.083

V = 268.083 $mm^{3}$ so go with A.

7 0

3 years ago

True [87]

Answer:

Step-by-step explanation:

4 0

3 years ago

Given a collection of paired sample data, the ____________ algebraically describes the relationship between the two variables, x

NNADVOKAT [17]

Data may be the answer

7 0

3 years ago