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natita [175]
2 years ago
5

Use the table from problem 1 to complete this problem.

Mathematics
1 answer:
artcher [175]2 years ago
3 0

Answer:

C

Step-by-step explanation:

M is t so 15x400 will b C

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The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0. When the product of factors equals zero, one or more of the factors must also equal zero. Once the polynomial is factored, set each factor equal to zero and solve them separately.
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3 years ago
Karim wants to buy a shirt that normally sells for $46.50. It is on sale for One-third off. How much does Karim need to pay to b
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Answer:

Step-by-step explanation:

First I took the original price of the shirt (46.50) since it is going one third off I divided it by 3 (46.50/3=15.50)

I took away the one third I divided from it (46.50-15.50=31)

I got 31 dollars as my final answer.

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3 years ago
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(1+tanx)/(sinx+cosx)=secx
jek_recluse [69]

\frac{1+\tan x}{\sin x+\cos x}=\sec x is proved

<h3><u>Solution:</u></h3>

Given that,

\frac{1+\tan x}{\sin x+\cos x}=\sec x  ------- (1)

First we will simplify the LHS and then compare it with RHS

\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}  ------ (2)

\text {We know that } \tan x=\frac{\sin x}{\cos x}

Substitute this in eqn (2)

=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}

On simplification we get,

=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}

=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}

Cancelling the common terms (sinx + cosx)

=\frac{1}{c o s x}

We know secant is inverse of cosine

=\sec x=R . H . S

Thus L.H.S = R.H.S

\frac{1+\tan x}{\sin x+\cos x}=\sec x

Hence proved

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3 years ago
Can I please help me with this question
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