Answer:
Sorry need to do some thing else brb
Step-by-step explanation:
Her profit was 126$ because she spent 24$ on her materials and then charged 5$ per 2 so you get 150$ then subtract the 24
(I think)
(7,3) because if you plug the 7 in for x and 3 in for y in both equations you get the right answer
A game is played using one die. If the die is rolled and shows 1, the player wins $5. If the die shows any number other than 1, the player wins nothing. If there is a charge of $1 to play the game, what is the game's expected value?
--------------------
Let random variable "x" be a count of player gain.
X-values are: 4, -1
P(x=4) = 1/6; P(x= -1) = 5/6
---------------------------------
E(x) = (1/6)(4) + (5/6)(-1)
E(x) = [4-5]/6
E(x) = -1/6 = -17 cents
=============================
Cheers,
