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Viktor [21]
2 years ago
12

Introduction to Functions quiz answers?

Mathematics
1 answer:
larisa86 [58]2 years ago
6 1

Answer:

hgdgcvwjhmcvtuqyjbwq jxghqnwukdhjqwnoukjxqexqe

Step-by-step explanation:

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A group of people were asked whether they watch television or read newspaper to get daily news.
kenny6666 [7]
<span>Watching television and reading newspaper are not independent events because P(A|B)=P(A) and P(B|A)=P(B) .
 I might be wrong so try to look at it a little closer before you take my word for it.
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7 0
3 years ago
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Pls help me with this pls
Virty [35]
(Sorry if I get something wrong, it’s straining my eyes to see what letter) 1. A 2. U 3. S 4. J 5. I 6. M 7. H 8. B 9. Y 10. L


To find where a coordinate is on a graph you need to start with the first number (x) (let’s say the coordinate is (2, -3), so 2) and find where it is ( you always find where the first number is on the x-axis and the second number on the y, remember that by x, y and x comes first.) Then, you need to find the second number (-3) then you need to find where they meet. So 2, -3 is on the letter I.

To find what coordinates a point that’s already been plotted is to see, for example, L, the two numbers that meet where L is are -4, -3, remember whatever was on the x axis comes first, -3, -4 is not the same.

Hopefully this makes sense, I don’t normally answer stuff.
6 0
3 years ago
What is the positive square root of 36? Enter your answer in the box.
cupoosta [38]
The answer to this question is going to be negative 6


6 0
3 years ago
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30= 2w + 2h<br><br> W= 3/4 h
Alexeev081 [22]

Answer:

h=60/7

w=45/7

Step-by-step explanation:

just try it.

7 0
3 years ago
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Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
3 years ago
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