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Alex Ar [27]
2 years ago
11

HELPPPPPPPPPPP MEEEEEEEEEEEEEE

Mathematics
2 answers:
Mama L [17]2 years ago
8 0

Answer:

i agree with the guy above it is correct

Step-by-step explanation:

QveST [7]2 years ago
3 0

Answer:

p < −9

Step-by-step explanation:

Divide each term in 9p<−81 by 9 and simplify

Inequality Form: p < -9

Interval Notation: (−∞,−9)

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Slope-intercept form (-3,-4);=-5x+5
Harlamova29_29 [7]

Answer:

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8 0
2 years ago
Use the Two-Transversal Proportionality Corollary to find the value of x.
Artist 52 [7]
I hope this helps you




12/12+x=13/13+26



12/12+x=13/39



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12+x=36


x=24
5 0
2 years ago
Read 2 more answers
HELP ASAP PLEASE <br> Not understanding and need answers asap
Neko [114]

Answer:

you domb if you dont know the answer B

Step-by-step explanation:

7 0
2 years ago
Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x&gt;1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)
\iff2=b+c

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)
\iff2=2b+c

Now we solve for b and c:

\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2
5 0
3 years ago
Solve using elimination.<br><br> –9x − 7y = –10<br> 9x + 8y = 5
guapka [62]

Answer:

x=4y

Step-by-step explanation:

mathpapa

7 0
2 years ago
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