Question

Please help me, im in tears because i cant figure this out. Litterly giving away my 100 points. Please answer correct, im begging.
The figure below shows a triangular piece of cloth:

Triangle ABC has angle ABC equal to 90 degrees and angle BAC equal to 35 degrees. Length of AC is 8 inches.

What is the length of the portion BC of the cloth?

8 cos 35°
sin 35 degrees divided by 8
cos 35 degrees divided by 8
8 sin 35°

Answer 1

<B=90

• AC=8in

We know

$\\ \sf\longmapsto Cos\Theta=\dfrac{Base}{Hypotenuse}$

$\\ \sf\longmapsto cos35=\dfrac{BC}{AC}$

$\\ \sf\longmapsto BC=ACcos35$

$\\ \sf\longmapsto BC=8cos35$

Option A

Answer 2

Answer:

The length of the portion BC of the cloth is 4.56 inches long.

Step-by-step explanation:

I suggest drawing the triangle out! It'll make it a lot easier to solve!

    A

      |35\    8 inches

      |       \

  B |90   _\ C

     x inches

Here you can use SOH CAH TOA

SOH = Sin theta =  Opposite/Hypotenuse

CAH = Cos theta =  Adjacent/Hypotenuse

TOA = Tan theta =  Opposite/Adjacent

We are going to use Sin because we have the hypotenuse and we're solving for opposite.

Sin theta (angle) = Opposite/Hypotenuse

Sin (35) = x/8

Sin (35) = 0.57 (Use a calculator)

0.57 = x/8  Now we're going to solve for x (segment BC)

0.57*8 = x

4.56 = x

The length of the portion BC of the cloth is 4.56 inches long.