Answer:
The answer will just be 125b^4
Step-by-step explanation:
Basically multiply 5 by 5 by 5 and then count all of the b’s (4 b’s) and add it to the product as an exponent
Final answer: 125b^4
The incorrect rounding for 53.864 is 53.87
<h3>How to approximation a decimal?</h3>
The decimal to be approximated is as follows;
53.864
The first option rounded the decimal to 2 significant figures or a whole number.
The second option is incorrect because they rounded it wrongly to 2 decimal places. The correct 2 decimal round is 53.86.
The third option is approximated rightly to one decimal place.
The last option is rounded to the closes tens term.
learn more on approximation here: brainly.com/question/9608644
#SPJ1
X² + 4x + 4 = 25
(x+2)² = 25
x + 2 = <span>±5
x + 2 = -5 or x + 2 = 5
x = -5 -2 x = 5 - 2
x = -7 x = 3
</span><span>The solutions are x=-7 and x=3</span>
Answer:
The P-value is 0.0234.
Step-by-step explanation:
We are given that a statistics practitioner calculated the mean and the standard deviation from a sample of 400. They are x = 98 and s = 20.
Let = population mean.
So, Null Hypothesis, : = 100 {means that the population mean is equal to 100}
Alternate Hypothesis, : > 100 {means that the population mean is more than 100}
The test statistics that will be used here is One-sample t-test statistics because we're yet to know about the population standard deviation;
T.S. = ~
where, = sample mean = 98
s = sample standard deviation = 20
n = sample size = 400
So, the test statistics = ~
= -2
The value of t-test statistics is -2.
Now, the P-value of the test statistics is given by;
P( < -2) = 0.0234 {using the t-table}
Answer:
Step-by-step explanation:
hello,
i advice you check the question again if it is GF(
) or GF(24). i believe the question should rather be in this form;
multiplication in GF(
): Compute A(x)B(x) mod P(x) =
+
+1, where A(x)=
+1, and B(x)=
.
i will solve the above question and i believe with this you will be able to solve any related problem.
A(x)B(x)=
= 
=
please note that the division by the modulus above we used
