First, we need to get POH value & we can get it from this formula:
PH + POH = 14
when we have PH = 8.59
∴ POH = 14 - 8.59 = 5.41
then, we need to get [OH-] & we can get it using POH:
POH = -㏒[OH]
5.41 = -㏒[OH]
∴ [OH] = 3.89 x 10^-6
when Ksp = [Fe2-][OH-]^2
and when we have Ksp = 4.87 x 10^-17
so, by substitution:
4.87 x 10^-17 = [Fe2-] * (3.89 x 10 ^-6)^2
∴[Fe2-] = 3.22 x 10^-6 M
∴ above 3.22 x 10^-6 M of Fe2+ , Fe(OH)2 will precipitate
Answer:
n = 0.0102 mol.
Explanation:
Hello there!
In this case, according to the ideal gas law, which allows us to set up a relationship among volume, pressure, temperature and moles, we can define it as:
Thus, given the volume in liters (0.1000 L), temperature in kelvins (298.15 K) and pressure in atmospheres (2.50 atm), we can solve for moles as shown below:
Thereafter, we plug in the aforementioned values to obtain:
Best regards!
Explanation:
Mixture is the physical Combination Of two or Substance
Example
a mixture of sugar and water.
Compound is the chemical combination of two or more metals.
Example.
a mixture of hydrogen and water.
A mixture of hydrogen and oxygen forms water or H2O
whereas The dihydrogen monoxide parody involves calling water by an unfamiliar chemical name, most often "dihydrogen monoxide" (DHMO), and listing some of water's properties in a particularly alarming manner, such as accelerating corrosion (rust) and causing suffocation (drowning). The parody often calls for dihydrogen monoxide to be banned, regulated, or labeled as dangerous. It plays into chemophobia and demonstrates how a lack of scientific literacy and an exaggerated analysis can lead to misplaced fears. The parody has been used with other chemical names such as hydrogen hydroxide, dihydrogen oxide, hydroxic acid, hydric acid and oxidane.
A dissociation reaction occurs.lets say pcl5=pcl3+cl2
Answer:
of the stock solution would be required.
Explanation:
Assume that a solution of volume contains a solute with a concentration of . The quantity of that solute in this solution would be:
.
For the solution that needs to be prepared, . The volume of this solution is . Calculate the quantity of the solute (magnesium chloride) in the required solution:
.
Rearrange the equation to find an expression of volume , given the concentration and quantity of the solute:
.
Concentration of the solute in the stock solution: .
Quantity of the solute required: .
Calculate the volume of the stock solution that would contain the required of the magnesium chloride solute:
.