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Nataly_w [17]
3 years ago
6

I just need help on 4 and 5 please ​

Chemistry
1 answer:
vampirchik [111]3 years ago
8 0

Answer:

4. 12 km.

5. 2 km.

Explanation:

Hello!

In this case, we need to distinguish between two terms:

- Distance traveled: it stands for the total displacement, no matter the initial and final position the body has; it means that the total displacement was:

DT = 3km + 4 km + 3 km + 2 km = 12 km.

- Displacement: it stands for the relationship between the initial position and the final one, it means that the initial position was 0 km and the final one is 2 km away, thus, the displacement is:

D = 2km - 0 km = 2 km.

Best regards!

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A hockey puck moving at 28 m/s is caught by an 80.00 kg man who was at rest the man and puck moved together after the collision.
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Answer: The final velocity of both man and hokey puck will be 0.056 m/s.

Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.

This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.

Sum of Initial momentum of two objects = Sum of Final momentum of the two objects

Mathematically,

m_1u_1+m_2u_2=m_1v_1+m_2v_2     ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of the first object.

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of the second object.

Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

m_1=80.00kg\\m_2=0.16kg\\u_1=0m/s\\u_2=28m/s\\v_1=v_2=V=?m/s

Putting values in equation 1, we get:

80(0)+0.16(28)=(0.80+0.16)V

V=0.056m/s

The final velocity of man and hockey puck is 0.056 m/s.

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3 years ago
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Cause it’s is the same
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Given the balanced equation representing a reaction at 101.3 kPa and 298 K:
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Answer:

Explanation:

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If total pressure be P

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= 11.67 x 10⁵ Pa

Kp  = Kc x ( RT )^{\triangle n}

\triangle n = 1

11.67 x 10⁵ = Kc x ( 8.31\times 600 )^{1}

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