Answer: The final velocity of both man and hokey puck will be 0.056 m/s.
Explanation: We are given 2 objects and are undergoing collision. The final velocity of both the objects is same. To calculate the final velocity, we will use the principle of conservation of momentum.
This principle states that when the objects that are colliding makes up a system, then the total momentum will remain constant if no external force is applied on it.
Sum of Initial momentum of two objects = Sum of Final momentum of the two objects
Mathematically,
...(1)
where,
are the mass, initial velocity and final velocity of the first object.
are the mass, initial velocity and final velocity of the second object.
Here, man and hockey puck are moving together after the collision, so their final velocities will be same.

Putting values in equation 1, we get:


The final velocity of man and hockey puck is 0.056 m/s.
Answer: (1) It is exothermic and DH equals -91.8 kJ.
Explanation: 
There are two types of reactions in terms of heat:
Endothermic reactions are those reactions in which heat is absorbed by the system and exothermic reactions are those reactions in which heat is released by the system.
As the heat is given on the products side, it means the heat is released in the reaction and thus the reaction is exothermic. The enthalpy change for exothermic reaction is written as negative and the enthalpy change for endothermic reaction is written as positive.
Answer:
Explanation:
PCl₅ ⇄ PCl₃ + Cl₂
1 mole 1 mole 1 mole
molecular weight of PCl₅ = 208.5
molecular weight of PCl₃ = 137.5
molecular weight of Cl₂ = 71
moles of PCl₅ = .0185
moles of PCl₃ = .0924
moles of Cl₂ = .1873
Total moles = .2982 moles
mole fraction of PCl₅ = .062
mole fraction of PCl₃ = .31
mole fraction of Cl₂ = .628
If total pressure be P
partial pressure of PCl₅ = .062 P
partial pressure of PCl₃ = .31 P
partial pressure of Cl₂ = .628 P
Kp = .31 P x .628 P / .062 P
= 3.14 P
To calculate Total pressure P
PV = nRT
P x 4 x 10⁻³ = .2982 x 8.31 x 600
P = 371.7 x 10³
= 3.717 x 10⁵ Pa
Kp = 3.14 P = 3.14 x 3.717 x 10⁵ Pa
= 11.67 x 10⁵ Pa
Kp = Kc x 
= 1
11.67 x 10⁵ = Kc x 
Kc = 234
The answer to your question is two protons and two neutrons.