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Mekhanik [1.2K]
3 years ago
7

For every touchdown scored by the Timberwolves, the mascot does 3 back flips and the cheerleaders set off 6 confetti cannons.

Mathematics
2 answers:
harkovskaia [24]3 years ago
5 0
Pretty sure it’s 3? bc 18/6=3 so. yea
SSSSS [86.1K]3 years ago
4 0

Answer:

3 Touchdowns

Step-by-step explanation:

1 touchdown for every 6 confetti cannons. If there were 18 cannons then 18 divided by 6 is 3. So 3 touchdowns.

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What is the value of i^n if the remained of n/4 is 2<br> A. i<br> B. -i<br> C. -1<br> D. 1
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Pete began practicing at twenty-five minutes before eight. What is another way to write this time?
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A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean
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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
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