The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
Answer:
ok so i think your gonna haveto use addition tell me if im wrong
Step-by-step explanation:you have a blessed thanksgiveing
Answer:
9x-y = 5
Step-by-step explanation:
Equation of line in slope intercept form:
y-y1 = m*(x-x1), m=9, (x1,y1)=(4,31)
y-31 = 9*(x-4)
y-31 = 9x-36
9x-y = 36-31
9x-y = 5
Answer:
V = 54π cm³ ⇒ answer (C)
Step-by-step explanation:
∵ V = (πd²h)/8
∵ d = 6 cm
∵ h = 12 cm
∴ V = (π × 6² × 12) ÷ 8 = 54π cm³
Answer:
"You could add each number one by one in your head, and the total is your answer."
