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snow_lady [41]
3 years ago
5

What's the greatest common factor of: 2*2*2*2*3*3*3*5*2*2*3*3*3*7

Mathematics
2 answers:
erastova [34]3 years ago
5 0

the greater common factor is : a.2

Monica [59]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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Cherries are on sale for $16 for 4 pounds. Jordyn pays $88.00 for cherries to make a cobbler. How many pounds of cherries doses
Tamiku [17]
She bought 5.5 pounds of cherries


explanation-
88 divided by 16 would be 5.5
7 0
2 years ago
The lines below are perpendicular if the slope of the solid line is 4 what is the slope of the dashed line
const2013 [10]

Answer:

The slope of the dashed line is -\frac{1}{4}

Step-by-step explanation:

Perpendicular lines and slopes:

If two lines are perpendicular, the multiplication of their slopes is -1.

What is the slope of the dashed line

Perpendicular to a line with slope 4, so:

4m = -1

m = -\frac{1}{4}

The slope of the dashed line is -\frac{1}{4}

8 0
3 years ago
HELP PLS!!! ASAP
horrorfan [7]

Answer:

x(3 – 4)

Step-by-step explanation:

x^3y

/x^4y

get rid of y

x^3/x^4

subtract exponents

x(3 – 4)

Brainliest please ask me if you have more questions.

5 0
2 years ago
Read 2 more answers
Point A is located at (2, 6), and point M is located at (−1, 8). If point M is the midpoint of segment AB, find the location of
Viefleur [7K]

ANSWER:

d. (−4, 10)

STEP-BY-STEP EXPLANATION:

The midpoint has the following definition:

\left(x_m,y_m\right)=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)

We can calculate point B, using the following equations obtained taking into account the above:

\begin{gathered} x_m=\frac{x_1+x_2}{2} \\  \\ -1=\frac{2+x_2}{2} \\  \\ x_2+2=-2 \\  \\ x_2=-2-2=-4 \\  \\  \\ y_m=\frac{y_1+y_2}{2} \\  \\ 8=\frac{6+y_2}{2} \\  \\ y_2+6=16 \\  \\ y_2=16-6=10 \\  \\ \text{ Therefore, point B is located at \lparen-4, 10\rparen} \end{gathered}

The correct answer is: d. (−4, 10)

8 0
1 year ago
Find the differential of each function. (a) y = tan( 7t ) dy = Incorrect: Your answer is incorrect. (b) y = 4 − v2 4 + v2 dy =
Kisachek [45]

Answer:

(a) dy= 7sec^2(7t)dt\\\\(b) dy = \frac{-16v}{(4+v^2)^2} dv

Step-by-step explanation:

Given;

(a) y = tan (7t)

let u = 7t

y = tan(u)

du/dt = 7

dy/du = sec²(u)

\frac{dy}{dt} = \frac{dy}{du} *\frac{du}{dt}\\\\\frac{dy}{dt} = sec^2(u)* 7\\\\\frac{dy}{dt} =7sec^2(u)\\\\\frac{dy}{dt} = 7sec^2(7t)\\\\dy = 7sec^2(7t)dt

(b)  

y = \frac{4-v^2}{4+v^2}\\\\

let u = 4 - v²

du/dv = -2v

let v = 4 + v²

dv/du = 2v

y = \frac{4-v^2}{4+v^2}\\\\\frac{dy}{dv} = \frac{vdu-udv}{v^2} \\\\\frac{dy}{dv} =\frac{-2v(4+v^2)-2v(4-v^2)}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-8v-2v^3-8v+2v^3}{(4+v^2)^2}\\\\\frac{dy}{dv} =\frac{-16v}{(4+v^2)^2}\\\\dy = \frac{-16v}{(4+v^2)^2}dv

6 0
3 years ago
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