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snow_lady [41]
3 years ago
5

What's the greatest common factor of: 2*2*2*2*3*3*3*5*2*2*3*3*3*7

Mathematics
2 answers:
erastova [34]3 years ago
5 0

the greater common factor is : a.2

Monica [59]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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Which construction correctly shows how to bisect
Dvinal [7]

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Step-by-step explanation:

its A

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3 years ago
The ratio x:10 is equilvalent to 9:6. What is the value of x
Troyanec [42]

Answer: x=20/3=6.67

Step-by-step explanation:

To solve proportions, the most useful way is to use [cross multiplication], where we not multiply horizontally but as diagonally.

-----------------------------------------------------------------------------

Given

x:10=9:6

Cross Multiply

9·x=6·10

9x=60

Divide 9 on both sides

9x/9=60/9

x=20/3=6.67

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
Aisha recorded the heights, in centimetres, of some girls.
sertanlavr [38]

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The median is marked at 161cm instead of 162cm.

The right part of the box (the upper quartile) is marked at 172cm, while the interquartile range is 17cm, so the upper quartile should be at 154cm + 17cm = 171cm.

5 0
3 years ago
Find the square root of 167281 by division method
tensa zangetsu [6.8K]

Answer:

square root of 167281 is 409

Here's the Step-by-step explanation using division:

6 0
3 years ago
If you are using Cosine and need to solve for an unknown hypotenuse, you should...
kifflom [539]

Using cosine, we can find the hypotenuse by using the formula below;

hypotenuse = adjacent / cos ∅

<h3 /><h3 /><h3>Trigonometric ratios:</h3>
  • Trigonometric ratios are ratios of sides of a right angled triangle.
  • The simplest ratios are cosine, sine and tangent.

Using cosine, the hypotenuse side can be solved as follows:

cosine ∅ = adjacent / hypotenuse

cross multiply

hypotenuse cos ∅ = adjacent

divide both sides by cos ∅

hypotenuse cos ∅ / cos ∅ = adjacent / cos ∅

Therefore,

hypotenuse = adjacent / cos ∅

learn more on cosines here: brainly.com/question/10657732?referrer=searchResults

6 0
2 years ago
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