Answer: ![1-(\frac{364}{365})^n](https://tex.z-dn.net/?f=1-%28%5Cfrac%7B364%7D%7B365%7D%29%5En)
Step-by-step explanation:
Binomial probability formula :-
, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.
We assume that the total number of days in a particular year are 365.
Then , the probability for each employee to have birthday on a certain day :
![p=\dfrac{1}{365}](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7B1%7D%7B365%7D)
Given : The number of employee in the company = n
Then, the probability there is at least one day in a year when nobody has a birthday is given by :-
![P(x\geq1)=1-P(x](https://tex.z-dn.net/?f=P%28x%5Cgeq1%29%3D1-P%28x%3C1%29%5C%5C%5C%5C1-P%280%29%5C%5C%5C%5C%3D1-%28%5EnC_0%28%5Cfrac%7B1%7D%7B365%7D%29%5E0%281-%5Cfrac%7B1%7D%7B365%7D%29%5En%29%5C%5C%5C%5C%3D1-%281%29%28%5Cfrac%7B364%7D%7B365%7D%29%5En%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bsince%7D%5C%20%5EnC_0%3D1%5D%5C%5C%5C%5C%3D1-%28%5Cfrac%7B364%7D%7B365%7D%29%5En)
Hence, the probability there is at least one day in a year when nobody has a birthday =![1-(\frac{364}{365})^n](https://tex.z-dn.net/?f=1-%28%5Cfrac%7B364%7D%7B365%7D%29%5En)
Answer:
Congruent triangles are triangles that have the same size and shape.
We say that the two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.
Step-by-step explanation:
The keyword is Rise over run
So the 2nd y value minus the first y value and divide it by the 2nd x value minus
(y2-y1)/(x2-x1)
(10-7)/5-3)
the first x value and you should get 3/2
*dont worry the if the number is under and not above it’s not a saying to do to the power of but it’s just saying the order in which to put the x and y values.