Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
The first one. Hope this helps
Be glad to tell me if it’s correct or not
vol of wheat bag = 1.96 mater cuba so 258.72 / 1.96 = 392 bags I think this is the anwers. if wrong then sorry
Answer:
k=-j=15
Step-by-step explanation:
See attachment for step by step :)
You want the (positive) distance when the height is 0, 0= -d^2 + 10d +5.
You would factor that out(You'd get radicals), and the final answer would be
<span>5±<span>30<span>−−</span>√</span></span><span>
You'd take the only positive one of the two, 5 + srt(30)
I hope I did that right :/</span>
