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jeyben [28]
3 years ago
15

A customer in Lowe's needs help. Matt works in shipping and receiving. It isn't Matt job to work with the customer, but he knows

what they need and how to help them. it will take 2 minute of matt time. what should matt do?
Computers and Technology
2 answers:
patriot [66]3 years ago
6 0
The answer to your question is 40.
klio [65]3 years ago
5 0

Answer:

40

Explanation:

hhhhhjjjj

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Declare an array named tax rates of five elements of type double and initialize the elements (starting with the first) to the va
inysia [295]

Answer:

"double tax_rates[5]= {0.10, 0.15, 0.21, 0.28, 0.31};" is the correct answer for the above question.

Explanation:

  • An array is a user-defined data type that is used to define the multiple variables of a single type in a continuous storage location.
  • In the C-programming language, When the user wants to declare an array he needs to define with the help of data type and size of the array with the help of the following syntax-- "Data_type variable_name [size_of_the_array];".
  • When the user wants to initialize the static value in the array then he can do that by the help of following syntax: "Data_type variable_name [size_of_the_array]={first_value,second_value,....,last_value};
  • The above question asked to defined the array of tax_rates name of type double with the above-defined value then he can do that with the help of above-defined syntax (which is defined in the answer part).
4 0
3 years ago
NOTE: in mathematics, division by zero is undefined. So, in C , division by zero is always an error. Given a int variable named
Sergio [31]

Answer:

#include <stdio.h>

int main()

{

   int callsReceived, operatorsOnCall;

   scanf("%d", &callsReceived);

   scanf("%d", &operatorsOnCall);

if(callsReceived>=0 && operatorsOnCall>0)

{

   printf("%d",callsReceived/operatorsOnCall);

}

else

{

   printf("INVALID") ;

} }

Explanation:

The programming language to use here is C.

There is an int type variable named callsReceived    

Another int type variable is operatorsOnCall

scanf is used to read values into callsReceived and operatorsOnCall

printf is used to print the number of calls received per operator which is found by dividing the calls received with the operators on call i.e. callsReceived / operatorsOnCall

Here the callsReceived is the numerator and should be greater than or equal 0 and operatorsOnCall is the denominator and should be less than 0. So an IF condition is used to check if the value stored in operatorsOnCall is greater than 0 and if the value stored in callsReceived is greater than or equal to 0 in order to precede with the division. AND (&&) logical operator is used to confirm that both these conditions should  hold for the IF statement to evaluate to TRUE.

In case the input is not valid, the else part is displayed which means that the message INVALID will be displayed.

In C++ cin is used to read from callsReceived and operatorsOnCall and cout is used to display the results of division or the INVALID message in case the IF condition is false. Rest of the code is the same.

cin >> callsReceived;

cin >> operationsOnCall;

if(callsReceived>=0 && operatorsOnCall>0)

   cout << (callsReceived/operationsOnCall);

else

   cout << "INVALID";

8 0
3 years ago
Audacity functions with a computer that has a minimum of ______ of RAM and a 300 MHz processor.
soldier1979 [14.2K]
If i remember correctly...it should be 64 MB
Hope this helps
5 0
3 years ago
Read 2 more answers
Assume that grade is a variable whose value is a letter grade-- any one of the following letters: 'A', 'B', 'C', 'D', 'E', 'F',
d1i1m1o1n [39]

Answer:

switch (grade) {

 case 'A':

   acount++;

   break;

 case 'B':

   bcount++;

   break;

 case 'C':

   ccount++;

   break;

 case 'D':

   dcount++;

   break;

 case 'E':

   ecount++;

   break;

 case 'F':

   fcount++;

   break;

 case 'W':

   wcount++;

   break;

 case 'I':

   icount++;

   break;

}

Explanation:

6 0
3 years ago
The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of
Mice21 [21]

Solution:

The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of the name and selecting of ignoring all.

Thus the required right answer is B.

8 0
3 years ago
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