<h2>Answer:</h2>
<u>The apparent magnitude of an object only tells us how bright an object appears from Earth while the absolute magnitude is the apparent brightness of a star if it were viewed from a distance of 32.6 light-years</u>
<h2>Explanation:</h2>
The apparent magnitude of an object only tells us how bright an object appears from Earth. Alternatively, if we know the distance and the apparent magnitude of a star, we can calculate its absolute magnitude. There are three factors which control the apparent brightness of a star as seen from Earth which are how big it is, how hot it is, and how far away it is. The absolute magnitude is a measure of the star's luminosity or the total amount of energy radiated by the star every second.
Answer:
(a)
M = 1.898 x 10^27 kg
(b)
v = 13.74 km/s
(c) E = 0.28 N/kg
Explanation:
Time period, T = 3.55 days = 3.55 x 24 x 3600 second = 306720 s
Radius, r = 6.71 x 10^8 m
G = 6.67 x 10^-11 Nm^2/kg^2
(a)
M = 1.898 x 10^27 kg
(b) Let v be the orbital velocity
v = 13739.5 m/s
v = 13.74 km/s
(b) The gravitational field E is given by
E = 0.28 N/kg
Answer:
18.5 cm
Explanation:
From;
1/u + 1/v = 1/f
Where;
u= object distance = 86cm
image height = 23 cm
Radius of curvature = 37 cm
The radius of curvature (r) is the radius of the sphere of which the mirror forms a part.
Focal length (f) = radius of curvature (r)/2 = 37cm/2 = 18.5 cm
Therefore, the focal length of the mirror is 18.5 cm
Answer:
The ratio of apparent increase in volume of the liquid per unit rise of temperature to the original volume is called its coefficient of apparent expansion. ... Thus a liquid has two coefficients of expansion. Measurement of the expansion of a liquid must account for the expansion of the container as well.