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LUCKY_DIMON [66]

3 years ago

11

A box is moved 10 m across a smooth floor by a force F making a downward angle with the floor, so that there is effectively a 4

N force acting parallel to the floor in the direction of motion and a 3 N force acting perpendicular to the floor. The force F acts for 20 seconds. The impulse delivered to the box by the floor during this process has magnitude

1 answer:

Brut [27]3 years ago

6 0

Answer:

Zero

Explanation:

Impulse is defined as the change in momentum.

Impulse is also defined as the product of force and the time duration of application of the force.

In the given problem, since there is no motion in the vertical direction, therefore the velocity of the box along the vertical direction is zero. So, momentum of the box along the vertical is also zero.

Hence the change is momentum is also zero along vertical direction.

Thus the impulse delivered by the box is zero.

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The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.

Reika [66]

Answer:

$tan \theta = \mu_s$

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

$mg sin \theta - \mu_s R =0$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, $\theta$ the angle of the slope

$\mu_s R$ is the frictional force, with $\mu_s$ being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

$R-mg cos \theta = 0$

where

R is the normal reaction

$mg cos \theta$ is the component of the weight perpendicular to the slope

Solving for R,

$R=mg cos \theta$

And substituting into (1)

$mg sin \theta - \mu_s mg cos \theta = 0$

Re-arranging the equation,

$sin \theta = \mu_s cos \theta\\\rightarrow tan \theta = \mu_s$

This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of $\mu_s$ , the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

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It's absolute neutropihil count, also called ANC

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student saw a science fiction movie in which a spaceship was zooming through space. The sound of the engine was loud. However, h

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3 years ago

Read 2 more answers

how much energy must be absorbed by 20.0 g of water to change its temperature from 95 degrees celsius to 125 degrees celsius

Natalija [7]

Answer:

I got 2508 J

Explanation:

q=mct

125-95

= 30 * 4.18 * 20

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5 0

3 years ago

The base of a box is .45 m by .65 m. It weighs 8694 N. What is the pressure exerted on the floor by the box?

dimaraw [331]

Answer:

$Pressure = 29723.1\ N/m^2$

Explanation:

Given

$Force = 8694N$

$Length = 0.45m$

$Width = 0.65m$

Required

The force exerted on the floor by the box

First, calculate the area covered by the box (i.e. the base area)

$Base\ Area = Length * Width$

$Base\ Area = 0.45m * 0.65m$

$Base\ Area = 0.2925m^2$

Pressure is calculated as:

$Pressure = \frac{Force}{Area}$

$Pressure = \frac{8694N}{0.2925m^2}$

$Pressure = 29723.0769231\ N/m^2$

$Pressure = 29723.1\ N/m^2$ --- approximated

6 0

3 years ago