3 years ago

How would a graph of velocity vs. Time would look like, if there was no motion at all? (Draw your graph)

Physics

1 answer:

Y_Kistochka [10]3 years ago

7 0

Answer:

no motion means no velocity, so the y values willl always be 0 as ur time (x) value increses

Explanation:

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An object is moving on a horizontal frictionless surface. if the net force applied to the object in the direction of motion is d

sukhopar [10]

Answer:

doubled

Explanation:

F=ma1----------(1)

2F = ma2-------(2)

Divide 2nd equation by 1st one

we get a1×2=a2

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2 years ago

John runs around a 126.5 m circular track 3.5 times in 4.17 minutes. What is his average speed?

sdas [7]

Average speed = distance traveled / time

average speed = (126.5 m * 3.5 laps) / (4.17 min)

= 106.2 m/min

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3 years ago

It is epistemically possible that a completed physics might include which of the following propositions? O Souls and other spiri

ohaa [14]

Answer:

option D.

Explanation:

The correct answer is option D.

At present the knowledge of physics does not includes the study related to souls , other spiritual substance.

Physics does not give the answers of question like God created universe , matter is unreal, etc.

So, there might will be possibility that in future complete physics will give the answer of all these questions i.e. correct answer is All of the above.

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3 years ago

A particle starts from rest and has an acceleration function 5 − 10t m/s2 . (a) What is the velocity function? (b) What is the p

frez [133]

Explanation:

It is given that,

A particle starts from rest and has an acceleration function as :

$a(t)=(5-10t)\ m/s^2$

(a) Since, $a=\dfrac{dv}{dt}$

v = velocity

$dv=a.dt$

$v=\int(a.dt)$

$v=\int(5-10t)(dt)$

$v=5t-\dfrac{10t^2}{2}=5t-5t^2$

(b) $v=\dfrac{dx}{dt}$

x = position

$x=\int v.dt$

$x=\int (5t-5t^2)dt$

$x=\dfrac{5}{2}t^2-\dfrac{5}{3}t^3$

(c) Velocity function is given by :

$v=5t-5t^2$

$5t-5t^2=0$

t = 1 seconds

So, at t = 1 second the velocity of the particle is zero.

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3 years ago

After being accelerated through a potential difference of 5.33 kv, a singly charged carbon ion (12c) moves in a circle of radius

LekaFEV [45]

I'm stuck on the same question, as well :(

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3 years ago