Hello!
This is a problem about the general solution of a differential equation.
What we can first do here is separate the variables so that we have the same variable for each side (ex.
with the
term and
with the
term).


Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.

Then here, we just solve for
and we have our general solution.
![y=\sqrt[3]{\frac{1}{2}x^2-x+C}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B2%7Dx%5E2-x%2BC%7D)
We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.
Hope this helps!
I search and found different answers but the nearest is 24
Answer:
Step-by-step explanation: you brine is smart use it
3 1/9 or 3.11 because you get a remainder of 1.
Answer: (a)
Step-by-step explanation:
Suppose the original function is 
To shift it 2 units right, replace x by x-2 such that

So, the function becomes 