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Lesechka [4]
3 years ago
6

Can anyone help me please.

Mathematics
1 answer:
Delvig [45]3 years ago
3 0
How am I suppose to help you if I can’t see the words. It’s too blurry.
You might be interested in
X−8π=π someone help me answer this
Ann [662]

Answer:

x = 9

Step-by-step explanation:

First step, divide both sides by pi to get rid of it entirely; you should be left with x - 8 = 1 (because when you divide a value by itself, you always get 1, so pi divided by pi gives you 1)

Second step, add 8 to both sides, leaving you with x = 9

4 0
2 years ago
16) It cost DJ $32.06 for 14 gallons of gas. What would be the cost if she bought 20 gallons of
fgiga [73]

Answer:

$45.8

Step-by-step explanation:

32.06 / 14= 2.29

2.29x20=45.8

8 0
2 years ago
12x3 + 13x – 5<br> 2x – 1
salantis [7]

Answer:

ANSWER: 24x^4 - 12x^3 + 26x^2 - 23x + 5

Step-by-step explanation:

6 0
3 years ago
If x+ay =b and<br> ax-by=c <br> Then find out x , y . (with process)
n200080 [17]

Answer:

The solution of the given system of equations is,

x=\frac{b^2+ac}{a^2+b};\; y=\frac{ab-c}{a^2+b}

Step-by-step explanation:

The given equations are :

<em>x</em> + a<em>y</em> = b          .......(1)

a<em>x</em> - b<em>y</em> = c        .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is '<em>x</em>' and '<em>y</em>' from one of the two equations in terms of the another variable  and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of '<em>x</em>' in terms of '<em>y</em>' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

   <em>x</em> + a<em>y</em> = b ⇒ <em>x</em> = b - a<em>y</em>          ........(3)

Substitute the value of '<em>x</em>' from (3) in (2), we get

  a(b - a<em>y</em>) - b<em>y</em> = c

⇒ab - a²<em>y</em> - b<em>y</em> = c

⇒-a²<em>y</em> - b<em>y</em> = c - ab

⇒-<em>y</em>(a²+b) = c - ab

⇒<em>y</em>(a²+b) = ab - c

\implies y=\frac{ab-c}{a^{2}+b}

Now, substituting the above value of '<em>y</em>' in equation (3), we get

x=b-a(\frac{ab-c}{a^2+b})

\implies x=\frac{b(a^2+b)-a(ab-c)}{a^2+b}

\implies x=\frac{a^2b+b^2-a^2b+ac}{a^2+b}

\implies x = \frac{b^2+ac}{a^2+b}

Hence, the solution of the given system of equations is,

x = \frac{b^2+ac}{a^2+b} ;\; y = \frac{ab-c}{a^2+b}

5 0
3 years ago
Will give brainliest if its correct
MrRa [10]

Answer:

10000000000

Step-by-step explanation:

10000000000

5 0
2 years ago
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