X+6 is the answer to the question.
Answer:
all work is shown and pictured
I'm assuming the function is f(x) = (2x+8)/(x^2+5x+6). If so, make sure to use parenthesis to indicate that you're dividing all of "2x+8" over all of "x^2+5x+6" as one big fraction. Otherwise, things are ambiguous and it leads to confusion.
Side Note: x^2 means "x squared"
Factor the numerator: 2x+8 = 2(x+4)
Factor the denominator: x^2+5x+6 = (x+2)(x+3)
There are no common factors between the numerator and denominator. So there is nothing to cancel out.
Recall that you cannot divide by zero. Something like 1/0 is undefined.
We need to find the x values that cause the denominator to be zero.
Set the denominator equal to zero and solve for x
x^2+5x+6 = 0
(x+2)(x+3) = 0
x+2 = 0 or x+3 = 0
x = -2 or x = -3
The x values x = -2 or x = -3 will lead to the denominator being zero. This means that the vertical asymptotes are x = -2 or x = -3 as shown by the blue dashed vertical lines in the attached image.
Answer:
Bhahawry76654
Step-by-step explanation:
Gree
Step-by-step explanation:
Katie's deposits are positive: 23.87, 41.03, and 61.33.
Her withdrawals are negative: -4.34 -21.11, -8.78.
Sorted from least to greatest (most negative is least, most positive is greatest):
-21.11, -8.78, -4.34, 23.87, 41.03, 61.33
Katie started with $128. Add to it all the deposits and withdrawals:
128 − 21.11 − 8.78 − 4.34 + 23.87 + 41.03 + 61.33 = 220