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2 years ago

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A child is spinning a rock at the end of a 2 foot rope at a rate of 180 revolutions per minute. What is the approximate linear v

elocity of the rock when it is released.

2 answers:

harkovskaia [24]2 years ago

7 0

The velocity you want it to be

kondor19780726 [428]2 years ago

6 0

Answer:

A child is spinning a rock at the end of a 2-foot rope at the rate of 180 revolutions per minute (rpm).

Step-by-step explanation:

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Claudia is reading a book that has 360 pages. she read some of the book last week. she plans to read 46 pages. when she does, sh

gladu [14]

She read 242 pages. I got that by finding what (4/5) x (360) was which is 288 and then subtracted 46 to see what was left over which is 242

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2 years ago

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

Or

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

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3 years ago

I Need Help In #1-5

Citrus2011 [14]

If you are having trouble with ratios you can look at them as fractions. The first number being the numerator and the second number being the denominator or the other way around. When you are asked to find an equivalent ratio, you just have to find an equivalent fraction.

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3 years ago

A+ab+abc=bcb <br>what are the numbers!?

Fofino [41]

a=1 b= c=Step-by-step explanation:

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3 years ago

Please Help. Will give Brainliest.

mixas84 [53]

Answer:

translation.........

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2 years ago